是否可以在模型上构建以下查询而不是对原始 sql 使用 sequilize.query()
select
queue,
count(*) total,
sum(case when type = 'Proactive' then 1 else 0 end) proactive,
sum(case when type = 'Reactive' then 1 else 0 end) reactive
from "OpenIncidents"
group by queue
order by total DESC;
我厌倦了将 sequelize.fn() 用于聚合函数,但在文档中找不到任何关于聚合函数支持 CASE WHEN 的信息。
我目前正在使用原始查询
return sequelize.query(
`
SELECT
queue,
COUNT(*) total,
SUM(CASE WHEN type = 'Proactive' THEN 1 ELSE 0 END) proactive,
SUM(CASE WHEN type = 'Reactive' THEN 1 ELSE 0 END) reactive
FROM "OpenIncidents"
GROUP BY queue
ORDER BY total DESC;
`,
{ type: sequelize.QueryTypes.SELECT })
.then(queues => res.json(queues))
.catch(err => res.status(400).json(err));
有没有办法直接在 Sequelize 模型上做,如下所示
return OpenIncident.findAll({
attributes:[
'queue',
[sequelize.fn('COUNT', sequelize.col('id')), 'total'],
[sequelize.fn('SUM', CASE_WHEN_STATEMENT, 'proactive'],
[sequelize.fn('SUM', CASE_WHEN_STATEMENT), 'reactive']
],
group: ['queue'],
order: [sequelize.fn('COUNT', sequelize.col('id')), 'DESC']
})
最佳答案
一种解决方案是使用“Sequelize.literal()”,如下所示:
[Sequelize.fn('SUM', Sequelize.literal('CASE WHEN type = 'Proactive' THEN 1 ELSE 0 END')), 'proactive']
关于node.js - 在 Sequelize.js 的聚合函数中使用 case-when,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56379980/