ruby-on-rails - RoR : PSQL to ruby - .加入

Question

我意识到这是一个有点初级的问题，但我遇到了一道似乎无法逾越的墙。我有一个 friend 帮我写了这段 Postgres 代码，现在我正试图将它转换成 ruby​​，老实说，我不确定如何去做。我似乎找不到任何关于如何正确排序请求的所有部分的文档。

Postgres:

SELECT
        assets.id,
        count(assets_users.asset_id) as the_count
FROM assets
LEFT OUTER JOIN assets_users ON assets.id = assets_users.asset_id
WHERE asset_profile_id = 7
GROUP BY assets.id
HAVING count(*) > 0
ORDER BY the_count;

ruby :

def order_assets
  @order = Asset.select("assets.id").count("assets_users.asset_id").joins("LEFT OUTER JOIN assets_users ON assets.id = assets_users.asset_id").group("assets.id").having("count(*) > 0").order("assets_users.asset_id")
end

编辑:

新的 Ruby 代码:

def order_assets
  @order = Asset.select("assets.id, count('assets_users.asset_id) as the_count")
                .joins("LEFT OUTER JOIN assets_users ON assets.id = assets_users.asset_id")
                .group("assets.id")
                .having("count(*) > 0").order("the_count")
end

我希望所有黄色的 Assets 都在顶部，当有用户的 Assets 在下面填写时。

Answer 1

这是等效的代码:-

@order = Asset.select("assets.id, count(assets_users.asset_id) as the_count")
              .joins("LEFT OUTER JOIN assets_users ON assets.id = assets_users.asset_id")
              .where("asset_profile_id = ?", current_asset_profile_id)
              .group("assets.id")
              .having("count(*) > 0")
              .order("the_count")