我的 sql-fu 不强大,而且我确信我在尝试让它工作时遗漏了一些简单的东西。我有一组相当标准的表:
users
-----
id
name
carts
-----
id
user_id
purchased_at
line_items
----------
id
cart_id
product_id
products
--------
id
permalink
如果该用户购买了特定产品,我想获得每个用户购买购物车的总数。也就是说:如果他们购买的购物车中至少有一个具有特定永久链接的产品,我想要计算购买的购物车总数,而不管其内容如何。
购物车的定义是当 carts.purchased_at 不为空时。
select
u.id,
count(c2.*) as purchased_carts
from users u
inner join carts c on u.id = c.user_id
inner join line_items li on c.id = li.cart_id
inner join products p on p.id = li.product_id
left join carts c2 on u.id = c2.user_id
where
c.purchased_at is not NULL
and
c2.purchased_at is not NULL
and
p.permalink = 'product-name'
group by 1
order by 2 desc
purchased_carts 的数字出奇地高,可能与订单项总数乘以购物车数量有关?或许?我对结果感到很困惑。任何帮助将不胜感激。
最佳答案
这应该有所帮助:
select u.id,
count(*)
from users u join
carts c on c.user_id = u.id
where c.purchased_at is not NULL and
exists (
select null
from carts c2
join line_items l on l.cart_id = c2.id
join products p on p.id = l.product_id
where c2.user_id = u.id and
c2.purchased_at is not NULL
p.permalink = 'product-name')
group by u.id
order by count(*) desc;
exists 谓词是一个半连接。
关于postgresql - Postgres : Getting a total related count based on a condition from a related table,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38311124/