javascript - Sequelize options.nest in query() 方法不起作用

Question

我有一个像这样的原始查询

squelize.query(
   `select "order".id, "orderCustomer".id as "orderCustomer.id", "orderCustomer".forename as "orderCustomer.forename" 
    from orders as "order"
    join customers as "orderCustomer" on "orderCustomer".id = "order"."orderCustomerId"
    where "orderCustomer".forename ilike '%petra%';`,
{
    type: Sequelize.QueryTypes.SELECT, 
    model: order,
    nest: true,
    mapToModel: true
})

当我在 psql 中查询时，我得到了正确的结果集:

-[ RECORD 1 ]----------+------
id                     | 383
orderCustomer.id       | 446
orderCustomer.forename | Petra
-[ RECORD 2 ]----------+------
id                     | 419
orderCustomer.id       | 9
orderCustomer.forename | Petra

问题是，Sequelize 显然无法将其形成这种类型的数组

[
 {
   id: 383,
   orderCustomer: {
      id: 446,
      forename: 'Petra'
   }
 },
   ...
]

相反，我得到的是这样的:

[
 {
   id: 383,
   'orderCustomer.id': 446,
   'orderCustomer.forename': 'Petra'
 },
   ...
]

我是否需要在查询的选项对象中包含客户模型？

更新

我记录了我的查询结果。所有返回的订单实例上都有此属性 _options:

_options:{ 
   isNewRecord: false,
   _schema: null,
   _schemaDelimiter: '',
   raw: true, // <--------- possible cause?
   attributes: undefined 
}

不知何故，我无法在查询定义中将 options.raw 设置为 false!也许这就是为什么……

…sequelize will not try to format the results of the query, or build an instance of a model from the result (see docs > query() > options.raw)

有什么想法吗？

Answer 1

我正在使用您的解决方案:nest: true 并且效果很好!

[err, rows] = await to(sequelize.query(query,{ replacements: { search: '%'+search+'%', limit: limit, offset: skip}, type: sequelize.QueryTypes.SELECT,nest: true}));