我正在尝试从单个表的一列中获取值,而另一列可以匹配两种情况之一。
我的 table 看起来像:
CREATE TABLE user_event (
id SERIAL Primary Key,
session_id uuid NOT NULL,
event_name text NOT NULL,
event_value text NOT NULL
);
-- Test Values
INSERT INTO user_event(session_id, event_name, event_value)
VALUES ('0971ad0b-0b98-4f09-bc93-9ae15c45941b', 'Heading.Click', 'test'),
('0971ad0b-0b98-4f09-bc93-9ae15c45941b', 'Subheading.Click', 'test'),
('0971ad0b-0b98-4f09-bc93-9ae15c45941b', 'Paragraph.Click', 'test'),
('6a627852-5f2a-4884-9949-cf11edf73628', 'Heading.Click', 'test'),
('1e5ec268-34ea-464a-82d1-2cf1e1425df3', 'Heading.Click', 'test'),
('1e5ec268-34ea-464a-82d1-2cf1e1425df3', 'Subheading.Click', 'test'),
('1e5ec268-34ea-464a-82d1-2cf1e1425df3', 'Page.Impression', 'test');
-- Result
('0971ad0b-0b98-4f09-bc93-9ae15c45941b', '6a627852-5f2a-4884-9949-cf11edf73628')
我要(伪sql):
SELECT session_id
FROM user_event
WHERE event_name IS Heading.Click
AND other event_name's for the same session_id don't Contain Subheading.Click
OR
event_name IS Heading.Click
AND other event_name's for the same session_id must contain both (Subheading.Click,
Paragraph.Click)
到目前为止,我想出了一个非常低效的方法
SELECT session_id
FROM user_event
WHERE event_name = 'Heading.Click'
AND
(session_id not in (select session_id from user_event where event_name != 'Heading.Click')
OR
(session_id in (select session_id from user_event where event_name = 'Subheading.Click')
AND session_id in (select session_id from user_event where event_name = 'Paragraph.Click')
));
这是我用来测试它的 fiddle 设置。 http://sqlfiddle.com/#!17/a55a3/1
最佳答案
您可以将查询重写为
SELECT session_id
FROM user_event
GROUP BY session_id
HAVING
SUM(CASE WHEN event_name = 'Heading.Click' THEN 1 ELSE 0 END) >0
AND (
SUM(CASE WHEN event_name = 'Subheading.Click' THEN 1 ELSE 0 END) =0
OR (
SUM(CASE WHEN event_name = 'Subheading.Click' THEN 1 ELSE 0 END) > 0
AND
SUM(CASE WHEN event_name = 'Paragraph.Click' THEN 1 ELSE 0 END) > 0
)
)
不需要子查询,您可以使用条件聚合来匹配每个 session ID 的条件。
关于sql - 选择另一列必须匹配两个特定选项之一的位置,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52741940/