python - 无法设置 Celery 结果后端

Question

我的第一个 Celery 程序看起来像这样 - 我几乎遵循 getting started instructions :

from celery import Celery

import time

app = Celery(
    "celery_test",
    broker="redis://",
    backend="redis://"
)

@app.task
def greet(who):
    print(f"Hello {who}")

@app.task
def add(x, y):
    return x + y

@app.task
def long(sleep_time):
    time.sleep(sleep_time)

尝试通过 backend='redis://' 设置结果后端会在调用 celery -A celery_test worker --loglevel=info 时导致以下语法错误，这看起来像是 Celery 中的一个错误:

[2019-01-21 12:58:59,457: CRITICAL/MainProcess] Unrecoverable error: SyntaxError('invalid syntax', ('/Users/cls/anaconda3/lib/python3.7/site-packages/celery/backends/redis.py', 22, 19, 'from . import async, base\n'))
Traceback (most recent call last):
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/kombu/utils/objects.py", line 42, in __get__
    return obj.__dict__[self.__name__]
KeyError: 'backend'

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/worker/worker.py", line 205, in start
    self.blueprint.start(self)
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/bootsteps.py", line 115, in start
    self.on_start()
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/apps/worker.py", line 139, in on_start
    self.emit_banner()
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/apps/worker.py", line 154, in emit_banner
    ' \n', self.startup_info(artlines=not use_image))),
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/apps/worker.py", line 217, in startup_info
    results=self.app.backend.as_uri(),
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/kombu/utils/objects.py", line 44, in __get__
    value = obj.__dict__[self.__name__] = self.__get(obj)
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/app/base.py", line 1196, in backend
    return self._get_backend()
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/app/base.py", line 914, in _get_backend
    self.loader)
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/app/backends.py", line 70, in by_url
    return by_name(backend, loader), url
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/app/backends.py", line 50, in by_name
    cls = symbol_by_name(backend, aliases)
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/kombu/utils/imports.py", line 56, in symbol_by_name
    module = imp(module_name, package=package, **kwargs)
  File "/Users/cls/anaconda3/lib/python3.7/importlib/__init__.py", line 127, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 1006, in _gcd_import
  File "<frozen importlib._bootstrap>", line 983, in _find_and_load
  File "<frozen importlib._bootstrap>", line 967, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 677, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 724, in exec_module
  File "<frozen importlib._bootstrap_external>", line 860, in get_code
  File "<frozen importlib._bootstrap_external>", line 791, in source_to_code
  File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
  File "/Users/cls/anaconda3/lib/python3.7/site-packages/celery/backends/redis.py", line 22
    from . import async, base
                      ^
SyntaxError: invalid syntax

我想验证这确实是一个错误，而不是我的配置问题。另外，我宁愿开始异步编程，也不愿编写错误报告，因此我们将不胜感激。

Answer 1

看来 celery 还不能在 python 3.7 中运行，只能在 python 3.6 或更低版本中运行。您可以在 trouble in setting celery tasks backend in Python 中找到解决方法