我试图在我的数据库(postgresql)中的两个表之间建立一对一的关系。我在 python 中使用 SQLAlchemy。因此,我使用了文档本身中给出的示例。 one-to-one relationship
from sqlalchemy import Column, ForeignKey, Integer, String, Date, Float
from sqlalchemy import create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import relationship
Base = declarative_base()
class Parent(Base):
__tablename__ = 'parent'
id = Column(Integer, primary_key=True)
child = relationship("Child", uselist=False, back_populates="parent")
class Child(Base):
__tablename__ = 'child'
id = Column(Integer, primary_key=True)
parent_id = Column(Integer, ForeignKey('parent.id'))
parent = relationship("Parent", back_populates="child"
engine = create_engine('postgresql+psycopg2://testdb:hello@localhost/fullstack')
Base.metadata.create_all(engine)
这将创建两个表 parent 和 child。 现在我在父表和子表中插入值
from sqlalchemy import create_engine
from sqlalchemy.orm import sessionmaker
from test_databasesetup import Base, Parent, Child
engine = create_engine('postgresql+psycopg2://testdb:hello@localhost/fullstack')
Base.metadata.bind = engine
DBSession = sessionmaker(bind=engine)
session = DBSession()
parent = Parent()
session.add(parent)
session.commit() // insert in 'parent' table with id=1
// insert into child
child = Child(parent_id=1)
session.add(child)
session.commit()
child = Child(parent_id=1)
session.add(child)
session.commit()
使用相同的 parent_id 再次插入子项应该会引发错误,但记录已插入。
id | parent_id
----+-----------
1 | 1
2 | 1
这里应该怎么做才能让我只能插入一个父id对应的child。我不希望 child 有相同的 parent_id。
谢谢。
最佳答案
问题是您直接指定了字段parent_id
。在这种情况下,sqlalchemy
没有机会验证关系是否为一对一
。相反,使用关系:
# add new parent to the database
parent = Parent()
session.add(parent)
session.commit()
# insert new child for this parent
child = Child(parent=parent) # @note: this is the code change. \
# Here we refer to parent, not parent_id field
session.add(child)
session.commit()
# insert another child for the same parent:
# this will assign this new child to the parent, and will
# *remove* previous child from this parent
child = Child(parent=parent)
session.add(child)
session.commit()
另一个副作用是代码更简洁。还有一个是 sqlalchemy
可以自己找出外键,你不需要知道对象的 id
:
parent = Parent()
child = Child(parent=parent)
# it is enough to add only one related object, and the other (Child) will be added to session automatically
session.add(parent)
# we can commit only now, when we finished working on all the objects in the current session/transaction
session.commit()
此外,您可以将唯一约束添加到 Child.parent_id
字段作为额外的数据库级别检查,这在您的情况下会引发错误:
parent_id = Column(Integer, ForeignKey('parent.id'), unique=True)
关于python - SQLAlchemy 一对一关系创建多行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34458521/