我们正在从 Oracle 迁移到 Postgres。
这里是 SQL,我曾经从 employee_name 列中提取数据并用来报告。
但现在我不确定如何执行 regex_count 部分。 甲骨文数据库
with A4 as
(
select 'govinda j/INDIA_MH/9975215025' as employee_name from dual
)
select employee_name ,
TRIM(SUBSTR(upper(A4.employee_name),1,INSTR(A4.employee_name,'/',1,1)-1)) AS employee_name1,
TRIM(SUBSTR(upper(A4.employee_name),INSTR(A4.employee_name,'/',1,1)+1,INSTR(A4.employee_name,'_',1,1)-INSTR(A4.employee_name,'/',1,1)-1)) AS Country,
TRIM(SUBSTR(upper(A4.employee_name),INSTR(A4.employee_name,'_',1,1)+1,INSTR(A4.employee_name,'/',1,2)-INSTR(A4.employee_name,'_',1,1)-1)) AS STATE,
CASE WHEN REGEXP_COUNT(A4.employee_name,'_')>1 THEN 'WRONG_NAME>1_'
WHEN REGEXP_COUNT(A4.employee_name,'/')>2 THEN 'WRONG_NAME>2/'
WHEN TRIM(SUBSTR(upper(A4.employee_name),INSTR(A4.employee_name,'/',1,1)+1,INSTR(A4.employee_name,'_',1,1)-INSTR(A4.employee_name,'/',1,1)-1))NOT IN
('INDIA','NEPAL') THEN 'WRONG_COUNTRY'
ELSE 'CORRECT' END AS VALIDATION
from A4
在 Postgres 的帮助下,我能够将其转换为以下部分。
with A4 as
(
select 'govinda j/INDIA_MH/9975215025'::text as employee_name
)
select employee_name,
split_part(employee_name, '/', 1) as employee_name1,
split_part(split_part(employee_name, '/', 2), '_', 1) as country,
split_part(split_part(employee_name, '/', 2), '_', 2) as state
from A4
但验证部分无法转换。非常感谢任何帮助,因为我们是 postgres 的新手。
最佳答案
您可以创建自定义函数:
create or replace function number_of_chars(text, text)
returns integer language sql immutable as $$
select length($1) - length(replace($1, $2, ''))
$$;
使用:
with example(str) as (
values
('a_b_c'),
('a___b'),
('abc')
)
select str, number_of_chars(str, '_') as count
from example
str | count
-------+-------
a_b_c | 2
a___b | 3
abc | 0
(3 rows)
请注意,上述函数仅计算字符串中某个字符的出现次数,并未使用正则表达式,正则表达式通常开销更大。
regexp_count()
的 Postgres 等价物可能如下所示:
create or replace function regexp_count(text, text)
returns integer language sql as $$
select count(m)::int
from regexp_matches($1, $2, 'g') m
$$;
with example(str) as (
values
('a_b_c'),
('a___b'),
('abc')
)
select str, regexp_count(str, '_') as single, regexp_count(str, '__') as double
from example
str | single | double
-------+--------+--------
a_b_c | 2 | 0
a___b | 3 | 1
abc | 0 | 0
(3 rows)
关于postgresql - postgres 中的 REGEXP_COUNT,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52424275/