regex - 从字符串中获取整数

Question

我在数据库中有这样的数据

61/10#61/12,0/12,10/16,0/21,0/12#61/33,0/28#0/34,0/23#0/28

像10/16(没有#)这样的部分是无效的，不应该用于计算，

但所有其他都有下一个格式 min_hr + "/"+ min_hrv + "#"+ max_hr + "/"+ max_hrv

问题是通过下一个 psevdo 公式获取 AVG 值 [ summ(all(min_hrv)) + summ(all(max_hrv)) ]/count(all(min_hrv)) + all(max_hrv))，对于 axample 字符串结果将是 ((10 + 12 + 28 + 23) + (12 + 33 + 34 + 28))/8) == 22

我尝试的是:

SELECT regexp_replace(
    '61/10#61/12,0/12,10/16,0/21,0/12#61/33,0/28#0/34,0/23#0/28',
    ',\d+/\d+,', ',',
    'g'
);

删除无效数据但 10/16 仍在字符串中，结果是:

                  regexp_replace                  
--------------------------------------------------
 61/10#61/12,10/16,0/12#61/33,0/28#0/34,0/23#0/28

如果很好地清理字符串，我的计划将以这种方式拆分为数组，对于 max(不是完整的解决方案，有空字符串)，对于 min 没有解决方案:

SELECT 
    regexp_split_to_array(
        regexp_replace(
            '61/10#61/12,0/12,0/12#61/33,0/28#0/34,0/23#0/28',
            ',\d+/\d+,', ',',
            'g'
        )
        ,',?\d+/\d+#\d+/'
    );

结果是:

 regexp_split_to_array 
-----------------------
 {"",12,33,34,28}

然后计算数据，像这样:

SELECT ((
    SELECT sum(tmin.unnest)
    FROM
        (SELECT unnest('{10,12,28,23}'::int[])) as tmin
    ) 
    + 
    (
    SELECT sum(tmax.unnest)
    FROM
        (SELECT unnest('{12,33,34,28}'::int[])) as tmax
    ))
    /
    (SELECT array_length('{12,33,34,28}'::int[], 1) * 2)

可能有人知道解决此类问题的更简单正确的方法吗？

Answer 1

使用regexp_matches():

select (regexp_matches(
    '61/10#61/12,0/12,0/12#61/33,0/28#0/34,0/23#0/28', 
    '\d+#\d+/(\d+)', 
    'g'))[1]

 regexp_matches 
----------------
 12
 33
 34
 28
(4 rows)    

整个计算可能是这样的:

with my_data(str) as (
values
    ('61/10#61/12,0/12,10/16,0/21,0/12#61/33,0/28#0/34,0/23#0/28')
),
min_max as (
    select 
        (regexp_matches(str, '(\d+)#\d+', 'g'))[1] as min_hrv,
        (regexp_matches(str, '\d+#\d+/(\d+)', 'g'))[1] as max_hrv
    from my_data
)

select avg(min_hrv::int+ max_hrv::int) / 2 as result
from min_max;

       result        
---------------------
 22.5000000000000000
(1 row)