sql - 查询结果太多

标签 sql postgresql

我试图同时理解以下查询,

SELECT s.LAST_NAME||', '||s.FIRST_NAME||' '||COALESCE(s.MIDDLE_NAME,' ') AS FULL_NAME,
s.LAST_NAME,
s.FIRST_NAME,
s.MIDDLE_NAME,
s.STUDENT_ID,
ssm.SCHOOL_ID,
ssm.SCHOOL_ID AS LIST_SCHOOL_ID,
ssm.GRADE_ID ,
sg1.BENCHMARK_ID,
sg1.GRADE_TITLE,
sg1.COMMENT AS COMMENT_TITLE,
ssm.STUDENT_ID,
sg1.MARKING_PERIOD_ID,
sg1.LONGER_COURSE_COMMENTS,
sp.SORT_ORDER,
sched.COURSE_PERIOD_ID 
FROM STUDENTS s,
STUDENT_ENROLLMENT ssm ,
SCHEDULE sched 
LEFT OUTER JOIN STUDENT_REPORT_CARD_BENCHMARKS sg1 ON (
sg1.STUDENT_ID=sched.STUDENT_ID 
AND sched.COURSE_PERIOD_ID=sg1.COURSE_PERIOD_ID 
AND sg1.MARKING_PERIOD_ID IN ('0','442','445','450') 
AND sg1.SYEAR=sched.SYEAR) 
LEFT OUTER JOIN COURSE_PERIODS rc_cp ON (
rc_cp.COURSE_PERIOD_ID=sg1.COURSE_PERIOD_ID 
AND rc_cp.DOES_GRADES='Y') 
LEFT OUTER JOIN SCHOOL_PERIODS sp ON (sp.PERIOD_ID=rc_cp.PERIOD_ID) 
WHERE ssm.STUDENT_ID=s.STUDENT_ID  
AND ssm.SCHOOL_ID='1'  
AND ssm.SYEAR='2010' 
AND ('22-APR-11' BETWEEN ssm.START_DATE AND ssm.END_DATE OR (ssm.END_DATE IS NULL))  
AND (LOWER(s.LAST_NAME) LIKE 'la''porsha%' OR LOWER(s.FIRST_NAME) LIKE 'la''porsha%' ) 
AND sched.STUDENT_ID=ssm.STUDENT_ID AND sched.MARKING_PERIOD_ID IN ('0','444','446','447','445','448','450','443','449') 
AND ('22-APR-11' BETWEEN sched.START_DATE AND sched.END_DATE OR (sched.END_DATE IS NULL AND '22-APR-11'>=sched.START_DATE))     
ORDER BY s.LAST_NAME,s.FIRST_NAME

并修改它以返回正确的结果——只返回一个不同的人。当搜索任何特定的人时,将返回多个结果,因为 schedule.course_period_id 返回了唯一的值。由于在 course_period_id 字段上有几个左外连接但跨不同的表,我对修改查询的位置感到困惑。

最佳答案

我试图通过格式化您的查询并摆脱混合语法来帮助人们回答问题。不是真正的答案,但评论太长了:

    SELECT s.LAST_NAME || ', ' || s.FIRST_NAME || ' ' || COALESCE(s.MIDDLE_NAME,' ') 
      AS FULL_NAME,
    s.LAST_NAME, s.FIRST_NAME, s.MIDDLE_NAME, s.STUDENT_ID, 
    ssm.SCHOOL_ID, ssm.SCHOOL_ID AS LIST_SCHOOL_ID, ssm.GRADE_ID ,
    sg1.BENCHMARK_ID, sg1.GRADE_TITLE, sg1.COMMENT AS COMMENT_TITLE,
    ssm.STUDENT_ID, sg1.MARKING_PERIOD_ID, sg1.LONGER_COURSE_COMMENTS,
    sp.SORT_ORDER, sched.COURSE_PERIOD_ID 
    FROM STUDENTS s
      INNER JOIN STUDENT_ENROLLMENT ssm
        ON ssm.STUDENT_ID=s.STUDENT_ID   -- moved from WHERE to here
      INNER JOIN SCHEDULE sched 
        ON sched.STUDENT_ID=ssm.STUDENT_ID -- moved from WHERE to here
      LEFT OUTER JOIN STUDENT_REPORT_CARD_BENCHMARKS sg1 
        ON (    sg1.STUDENT_ID=sched.STUDENT_ID 
            AND sched.COURSE_PERIOD_ID=sg1.COURSE_PERIOD_ID 
            AND sg1.MARKING_PERIOD_ID IN ('0','442','445','450') 
            AND sg1.SYEAR=sched.SYEAR) 
      LEFT OUTER JOIN COURSE_PERIODS rc_cp 
        ON (    rc_cp.COURSE_PERIOD_ID=sg1.COURSE_PERIOD_ID 
            AND rc_cp.DOES_GRADES='Y') 
      LEFT OUTER JOIN SCHOOL_PERIODS sp 
        ON (sp.PERIOD_ID=rc_cp.PERIOD_ID) 
    WHERE ssm.SCHOOL_ID='1'  
      AND ssm.SYEAR='2010' 
      AND ('22-APR-11' BETWEEN ssm.START_DATE AND ssm.END_DATE 
           OR (ssm.END_DATE IS NULL))  
      AND (  LOWER(s.LAST_NAME) LIKE 'la''porsha%' 
           OR LOWER(s.FIRST_NAME) LIKE 'la''porsha%' ) 
    AND sched.MARKING_PERIOD_ID 
         IN  ('0','444','446','447','445','448','450','443','449') 
    AND (   '22-APR-11' BETWEEN sched.START_DATE AND sched.END_DATE 
         OR (     sched.END_DATE IS NULL
             AND '22-APR-11' >= sched.START_DATE))     
ORDER BY s.LAST_NAME, s.FIRST_NAME

希望对您有所帮助。

关于sql - 查询结果太多,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5781153/

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