sql - 如何将 YYYYMMDDHHMMSS 转换为 2013-11-24 11 :29:07 in postgres

Question

Postgres char(14) 字段存储没有分隔符的日期时间，例如 20131124112907

如何添加分隔符使结果为字符串格式

2013-11-24 11:29:07

我尝试使用 Denis 回答

to_timestamp(timestamp, 'YYYYMMDDHHMISS')::text as updated_at

但有异常

  Message=ERROR: 22007: hour "15" is invalid for the 12-hour clock
  Code=22007

  File=src\backend\utils\adt\formatting.c
  Hint=Use the 24-hour clock, or give an hour between 1 and 12.

Answer 1

您可以使用 to_date() 或 to_timestamp() 转换它:

select to_timestamp('20131124112907', 'YYYYMMDDHH24MISS')

http://www.postgresql.org/docs/current/static/functions-formatting.html#FUNCTIONS-FORMATTING-DATETIME-TABLE