java - 如何在 postgres 中没有时区的情况下节省时间。我正在使用 hibernate Spring MVC

Question

ERROR: column "receipt_time" is of type time without time zone but expression is of type bytea Hint: You will need to rewrite or cast the expression. Position: 490

private LocalTime receiptTime;
@Column(name = "receipt_time")
public LocalTime getReceiptTime() {
 return receiptTime;
}
public void setReceiptTime(LocalTime receiptTime) {
   this.receiptTime = receiptTime;
}

Answer 1

如果您想使用 LocalTime 那么您可以使用转换器:

@Converter
public class MyConverter implements AttributeConverter<LocalTime, Time> {

    @Override
    public Time convertToDatabaseColumn(LocalTime localTime) {
        if(localTime == null){
            return null;
        }

        // convert LocalTime to java.sql.Time
    }

    @Override
    public LocalTime convertToEntityAttribute(Time time) {
        if(time == null){
            return null;
        }

        // convert java.sql.Time to LocalTime
    }
}

然后在您的实体中您将使用:

@Column(name = "receipt_time")
@Convert(converter = MyConverter.class)
public LocalTime getReceiptTime() {
 return receiptTime;
}