我很难把DISTINCT ON子句翻译成knex.js
在join（）中使用多个andOn的过程中也可能会出现一些错误。
找不到正确翻译的方法。
select DISTINCT ON (f1.operdate) f1.operdate as date,
f2.operdate as opendate,
opercodes.naenter code hereme as name,
f1.person as person,
f1.comments as comments,
f2.person as conductor
from cashboxdiary as f1
inner join opercodes on (opercodes.id = f1.opercode)
inner join cashboxdiary f2 on (f2.company = f1.company and f2.cashbox = f1.cashbox and f2.opercode = 3 and f2.operdate < f1.operdate)
我到目前为止所做的努力
knex("cashboxdiary")
.innerJoin("opercodes", "opercodes.id", "cashboxdiary.opercode")
.join('cashboxdiary as f2',function () {
this.on('f2.company','=','cashboxdiary.company')
.andOn('f2.cashbox','=','cashboxdiary.cashbox')
.andOn('f2.opercode','=',knex.raw('?',[3]))
.andOn('f2.operdate','<','cashboxdiary.operdate');
})
.where({ "cashboxdiary.company": company, "cashboxdiary.cashbox": cashbox})
.whereNotIn("cashboxdiary.opercode", [3, 4, 5, 6])
.andWhereBetween(knex.raw("cashboxdiary.operdate::date"), [
dateFrom.format(),
dateTo.format()
])
.select(knex.raw('distinct on (cashboxdiary.operdate) cashboxdiary.operdate as date,f2.operdate as opendate, opercode.name as name, cashboxdiary.person as person, cashboxdiary.comments as comments, f2.person as conductor'))
最佳答案
是语法错误。应该这样写选择：
.select(knex.raw('distinct on(cashboxdiary.operdate) cashboxdiary.operdate as date'),'f2.operdate as opendate', 'opercode.name',...)
关于sql - 如何将SELECT DISTINCT ON转换为knex.js，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58410882/