我的数据点分布在全局各地。每个数据点都有一个时间戳。
我想按季节对数据进行分组,如下图所示(来源:https://en.wikipedia.org/wiki/Season#/media/File:Seasons1.svg)。
这是我迄今为止尝试过的(北半球 2011/2012 年冬季):
SELECT * FROM my_table
WHERE my_date BETWEEN '2011-12-21' AND '2012-03-21'
AND ST_Y(ST_Centroid(geom)) > 0;
我怎样才能在所有可能的年份里做到这一点?我尝试过...或日期之间...但这非常慢。
如何才能同时选择北半球和南半球的冬天?
更新
对于北半球的所有冬季数据,我使用以下查询:
CREATE TABLE season_winter_north AS WITH first_step AS (
SELECT
id,
extract(month from my_date)::int AS month,
extract(day from my_date)::int AS day,
ST_Centroid(geom) AS geom
FROM mytable
WHERE ST_Y(ST_Centroid(geom)) > 0)
(SELECT * FROM first_step
WHERE month = 12
AND day >= 21)
UNION ALL
(SELECT * FROM first_step
WHERE month = ANY('{1,2}'))
UNION ALL
(SELECT * FROM first_step
WHERE month = 3
AND day<21)
有更优雅或更高效的解决方案吗?
最佳答案
with t(my_date) as (
values ('2012-07-01'::date), ('2013-03-30'), ('2013-10-12'), ('2013-01-10')
)
select
case
when my_date between
make_date(extract(year from my_date)::int, 3, 21)
and
make_date(extract(year from my_date)::int, 6, 20)
then 'spring'
when my_date between
make_date(extract(year from my_date)::int, 6, 21)
and
make_date(extract(year from my_date)::int, 9, 22)
then 'summer'
when my_date between
make_date(extract(year from my_date)::int, 9, 23)
and
make_date(extract(year from my_date)::int, 12, 20)
then 'fall'
else 'winter'
end as season,
my_date
from t
;
season | my_date
--------+------------
summer | 2012-07-01
spring | 2013-03-30
fall | 2013-10-12
winter | 2013-01-10
关于PostgreSQL 按季节分组(北半球和南半球),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32393295/