postgresql - 将 View 名称作为参数传递给函数

Question

我可以将 View 的名称作为函数的参数传递吗？示例:

CREATE OR REPLACE FUNCTION example_test(test type_view) return void as $$
BEGIN
    start_ts = CLOCK_TIMESTAMP();
    REFRESH MATERIALIZED VIEW test;
    GET DIAGNOSTICS total_rows = ROW_COUNT;
    INSERT INTO control_dw_monitoring (name, start_time, end_time, total)
    VALUES ('view points that never contacted', start_ts, CLOCK_TIMESTAMP(), total_rows);
END
$$ language plpgsql;

Answer 1

尝试以下操作:

CREATE FUNCTION refresh_view_by_name(view_name text) RETURNS VOID AS $$
BEGIN
    EXECUTE 'REFRESH MATERIALIZED VIEW ' || view_name::regclass;
END
$$ LANGUAGE PLPGSQL;