sql - where 子句上的星期几和时间

Question

我有以下运行良好的 SQL 查询。根据行的时区，它在一个时间范围内获取行

SELECT *, (now() AT TIME ZONE account.timezone)::time AS local_time 
FROM contact INNER JOIN account ON account.id = contact.account_id 
WHERE (now() AT TIME ZONE account.timezone)::time BETWEEN '17:30'::time AND '22:00'::time

但如果是周末或工作日，我希望有不同的时间。在周末，我想要 15:30 而不是 17:30

如何使用 Postgresql 完成此操作？

Answer 1

使用EXTRACT(DOW FROM ...)得到星期几。然后使用 CASE ... END如果是星期六或星期日，则在 15:30 重新调整，否则在 17:30 重新调整。

SELECT *,
       (now() AT TIME ZONE account.timezone)::time AS local_time 
       FROM contact
            INNER JOIN account
                       ON account.id = contact.account_id 
       WHERE (now() AT TIME ZONE account.timezone)::time BETWEEN CASE
                                                                   WHEN EXTRACT(DOW FROM now() AT TIME ZONE account.timezone) IN (6, 0)
                                                                     THEN '15:30'::time
                                                                   ELSE
                                                                     '17:30'::time
                                                                 END
                                                                 AND '22:00'::time;