我创建了名为 t_user_type 的复合类型:
CREATE TYPE t_user_type AS
(uid integer,
firstname character varying,
lastname character varying,
companyname character varying,
email character varying,
sip_phone integer);
...我需要将字符串转换为该类型,所以我这样做了
SELECT '(11423, FirstName, LastName, Company, email@gmail.com, 204)' :: t_user_type;
一切都很好。没有错误,什么都没有。但是当我使用过程做同样的事情时,我得到了这个错误:Invalid input syntax for integer: "(11423,"FirstName","LastName","Company","email@gmail.com", 204) “。
这是我的程序:
CREATE OR REPLACE FUNCTION change_type(p_user character varying)
RETURNS void AS
$BODY$DECLARE
v_user_type t_user_type;
BEGIN
SELECT p_user :: t_user_type INTO v_user_type;
END;$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION change_type(character varying)
OWNER TO postgres;
这里是使用过程的查询:
SELECT change_type(
'(11423, FirstName, LastName, Company, email@gmail.com, 204)');
谁能告诉我我做错了什么?
最佳答案
不确定为什么会失败我做了一些小改动,我只是将值转换为您的局部变量并且它似乎可以工作。但我还不知道为什么。 SELECT INTO 变量是否像您所做的那样合法(我想我可以将常规文本字符串转换为文本变量)?当它只是一个没有源表的变量时,我通常会像下面的示例那样做。
CREATE TYPE t_user_type AS
(uid integer,
firstname character varying,
lastname character varying,
companyname character varying,
email character varying,
sip_phone integer);
SELECT '(11423, FirstName, LastName, Company, email@gmail.com, 204)' :: t_user_type;
CREATE OR REPLACE FUNCTION change_type(p_user character varying)
RETURNS t_user_type AS
$BODY$DECLARE
v_user_type t_user_type;
BEGIN
v_user_type := CAST(p_user AS t_user_type);
return v_user_type;
END;$BODY$
LANGUAGE plpgsql VOLATILE
COST 100;
ALTER FUNCTION change_type(character varying)
OWNER TO postgres;
SELECT change_type(
'(11423, FirstName, LastName, Company, email@gmail.com, 204)');
关于PostgreSQL - 整数的无效输入语法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21761037/