我有以下场景:
我有员工登记他们的工作 checkin / checkout 。但他们有 10 分钟的容忍度。
我使用此 View 得到的迟到条目:
CREATE OR REPLACE VIEW employees_late_entries
(
id,
created_datetime,
entry_datetime,
contact_id,
contact_name,
user_id,
employees_perm_id
)
AS
SELECT precence_records.id,
precence_records.created AS created_datetime,
("substring"(precence_records.created::text, 0, 11) || ' '::text) || contacts.entry_time::text AS entry_datetime,
contacts.id AS contact_id,
contacts.name AS contact_name,
precence_records.user_id,
precence_records.employees_perm_id
FROM precence_records,
contacts
WHERE
precence_records.type::text = 'entry'::text AND
contacts.employee = true AND
contacts.id = precence_records.contact_id AND
( ("substring"(precence_records.created::text, 0, 11) || ' '::text) || contacts.entry_time::text) < precence_records.created::text AND
precence_records.employees_perm_id IS NULL;
precence_records.created
是签到时间,contacts.entry_time
是员工的日程安排输入时间。
这是 contacts.entry_time
与 precence_records.created
获取迟到条目的条件:
( ("substring"(precence_records.created::text, 0, 11) || ' '::text) || contacts.entry_time::text) < precence_records.created::text
所以我想做这样的事情:
( ("substring"(precence_records.created::text, 0, 11) || ' '::text) || (contacts.entry_time::text + 10 MINUTES) ) < precence_records.created::text
数据类型:
precence_records.created 时间戳 contacts.entry_time VARCHAR
你能帮帮我吗
最佳答案
PostgreSQL 中的日期、时间和时间戳可以添加/减去 INTERVAL 值:
SELECT now()::time - INTERVAL '10 min'
如果你的timestamp字段是varchar,你可以先转成timestamp数据类型再减去interval:
( (left(precence_records.created::text, 11) || ' ') ||
(contacts.entry_time::time + INTERVAL '10min')::text )::timestamp <
precence_records.created::timestamp
关于sql - 如何从 postgreSQL 中的时间戳中减去/添加分钟,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37173732/