使用 postgresql 9.3(和新的 json awesomness)如果我有一个名为“races”的简单表,其中包含两列描述,例如:
race-id integer,
race-data json
而 json 是每场比赛的有效载荷,类似于
{ "race-time": some-date,
"runners": [ { "name": "fred","age": 30, "position": 1 },
{ "name": "john","age": 29, "position": 3 },
{ "name": "sam","age": 31, "position": 2 } ],
"prize-money": 200 }
如何查询表:
1) sam 获得第一名的比赛
2) sam 获得第一名而 john 获得第二名的比赛
3) 30岁以上参赛人数>5人且奖金>5000
到目前为止,我的实验(特别是在查询嵌套数组有效载荷方面)导致进一步规范化数据,即创建一个名为 runners 的表来进行此类查询。理想情况下,我想使用这个新的奇特的 json 查询功能,但我似乎无法对 3 个简单查询做出正面或反面的判断。
最佳答案
您可以展开 json 到一条记录中,然后根据需要进行查询(参见 json functions):
with cte as (
select
race_id,
json_array_elements(r.race_data->'runners') as d,
(r.race_data->>'prize-money')::int as price_money
from races as r
), cte2 as (
select
race_id, price_money,
max(case when (d->>'position')::int = 1 then d->>'name' end) as name1,
max(case when (d->>'position')::int = 2 then d->>'name' end) as name2,
max(case when (d->>'position')::int = 3 then d->>'name' end) as name3
from cte
group by race_id, price_money
)
select *
from cte2
where name1 = 'sam' and name2 = 'john'
由于您的 JSON 结构,它有点复杂。我认为如果您稍微改变一下结构,您的查询可能会简单得多:
{
"race-time": some-date,
"runners":
{
"1": {"name": "fred","age": 30},
"2": {"name": "sam","age": 31},
"3": {"name": "john","age": 29}
},
"prize-money": 200
}
你可以使用->>
和->
运算符或者json_extract_path_text
函数来获取你需要的数据,然后在中使用它>where
子句:
select *
from races as r
where
r.race_data->'runners'->'1'->>'name' = 'sam';
select *
from races as r
where
json_extract_path_text(r.race_data, 'runners','1','name') = 'sam' and
json_extract_path_text(r.race_data, 'runners','2','name') = 'john';
select *
from races as r
where
(r.race_data->>'prize-money')::int > 100 and
(
select count(*)
from json_each(r.race_data->'runners')
where (value->>'age')::int >= 30
) >= 2
关于json - 在 9.3+ 中查询嵌套负载的 Postgresql json,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20373954/