我在表中有以下数据:
+----------------------+----------------------------------------------------------+--------------+
| subscriber_fields_id | name | field_type |
+----------------------+----------------------------------------------------------+--------------+
| 143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi | Job Location |
| 146 | Karachi | Job Location |
| 147 | Lahore and Karachi | Job Location |
| 149 | Karachi, Mirpur Khas, Sukkur, Layyah, Gilgit, Charsaddah | Job Location |
| 152 | Islamabad or Lahore | Job Location |
| 155 | Islamabad | Job Location |
| 157 | 7 Districts of Sindh and Karachi | Job Location |
+----------------------+----------------------------------------------------------+--------------+
我的查询是:
select * from subscriberfields
where name like '%Khairpur,Islamabad,Karachi%';
结果:
+----------------------+-----------------------------------------------+--------------+
| subscriber_fields_id | name | field_type |
+----------------------+-----------------------------------------------+--------------+
| 143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi | Job Location |
| 152 | Islamabad or Lahore | Job Location |
| 155 | Islamabad | Job Location |
+----------------------+-----------------------------------------------+--------------+
它应该返回名称包含 Islamabad、Khairpur 或 Karachi 但实际上没有的所有行。
最佳答案
要获得合适的解决方案，normalize your database design或者，除此之外，请考虑 full text search .
要快速解决手头的问题，请使用 regular expression match (~)或三个简单的 LIKE表达式:
SELECT *
FROM subscriberfields
WHERE name ~ '(Khairpur|Islamabad|Karachi)';
或者:
...
WHERE (name LIKE '%Khairpur%'
OR name LIKE '%Islamabad%'
OR name LIKE '%Karachi%')
或者使用~*或者ILIKE进行不区分大小写的匹配。
因为另一个答案建议它:从不使用SIMILAR TO:
关于SQL查询以匹配多个字符串之一，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28938905/