我的代码裁剪了一张照片。裁剪后的照片会不断更换，但浏览器只会加载第一张裁剪的照片。我已经在网上搜索过，但没有任何效果。我已将随机字符串添加到 php - new.jpg?time=t - 但这会阻止裁剪图像的保存。我已经包括
<head>
<meta charset="utf-8">
<meta http-equiv="Cache-Control" content="no-cache, no-store, must-revalidate" />
<meta http-equiv="Pragma" content="no-cache" />
<meta http-equiv="Expires" content="-1" />
</head>
但浏览器仍然从缓存中加载。随后是 HTML JavaScript 和 PHP。还有其他建议吗？
<html>
<head>
<title>Image Crop</title>
<style>
body{
margin: 0;
padding: 0;
}
#container{
width: 300px;
}
#box{
position: absolute;
top: 0px;
left: 0px;
width: 100px;
height: 100px;
background: white;
border: 2px solid blue;
opacity: 0.5;
}
#crop_button{
background: #333;
color: #fff;
padding: 5px;
border: 0px;
margin: 5px;
}
#output{
position: absolute;
top: 0px;
left: 300px;
}
</style>
</head>
<body>
<div id="container">
<img src="resized_IMG0934.jpg"/>
<div id="box"></div>
</div>
<div id="output"><image />
</div>
<button id="crop_button">Crop</button>
<link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<script src="index.js"></script>
</body>
</html>
$(function() {
$('#box').draggable({containment: '#container'});
$('#box').resizable({containment: '#container'});
$('#crop_button').click(function(){
var top = $('#box').position().top;
var left = $('#box').position().left;
var width = $('#box').width();
var height = $('#box').height();
$.post('crop.php', {top:top, left:left, width:width, height:height}, function(){
$('#output').html('<img src="new.jpg"/>');
});
});
});
<?php
$dst_x = 0;
$dst_y = 0;
$src_x = $_POST['left']; //crop Start x
$src_y = $_POST['top']; //crop Start y
$dst_w = $_POST['width']; //Thumb width
$dst_h = $_POST['height']; //Thumb height
$src_w = $_POST['width']; //$src_w + $dst_w
$src_h = $_POST['height']; //$src_h + $dst_h
$dst_image = imagecreatetruecolor($dst_w,$dst_h);
$src_image = imagecreatefromjpeg("resized_IMG0934.jpg");
imagecopyresampled($dst_image, $src_image, $dst_x, $dst_y, $src_x, $src_y, $dst_w, $dst_h, $src_w, $src_h);
imagejpeg($dst_image, "new.jpg");
最佳答案
您有以下选择: - 添加以下元标记，这将强制不缓存
<meta http-equiv="pragma" content="no-cache" /> which you have already as I see
- 此外，如果要加载新版本的css文件，请执行以下操作
< link rel="stylesheet" type="text/css" href="mystyle.css?version={NewVersionOnRequierd}">
- 图片相同
< img src="picture.jpg?123" alt="">
关于javascript - 强制浏览器忽略缓存，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23734005/