javascript - 如何更改多维数组中的顺序然后在 javascript 中对一个子数组进行排序？

Question

当我对一个子数组进行排序时，如何根据已排序子数组的新顺序更改其他子数组元素的顺序:

var op = [];

op[0] = [0, "1:7001", "1:7002", "1:7003", "1:7004", "1:7005"];
op[1] = [1, "1:8001", "1:8002", "1:8003", "1:8004", "1:7005"];
op[2] = ["asw", 3, 5, 1, 10, 2];


op[2] = op[2].slice(0, 1).concat(op[2].slice(1, op[2].length).sort(function(a,b) {
    return b - a;
}));

console.log(op);

预期的数组应该是这样的:

[0, "1:7004", "1:7002", "1:7001", "1:7005", "1:7003"];
[1, "1:8004", "1:8002", "1:8001", "1:7005", "1:8003"];
[ "asw", 10, 5, 3, 2, 1 ]

Answer 1

您可以使用一个包含值对象和索引的临时数组进行排序，并将其他数组映射到已排序数组的索引。

这种方法称为 sorting with map .

var op = [
        [0, "1:7001", "1:7002", "1:7003", "1:7004", "1:7005"],
        [1, "1:8001", "1:8002", "1:8003", "1:8004", "1:7005"],
        ["asw", 3, 5, 1, 10, 2]
    ],
    order = op[2]                                  // take op[2] as pattern
        .slice(1)                                  // omit first element
        .map((v, i) => ({ v, i: i + 1 }))          // take value and index with offset
        .sort(({ v: a }, { v: b }) => b - a);      // sort by value desc

order.unshift({ i: 0 });                           // keep first item at index zero

op = op.map(a => order.map(({ i }) => a[i]));      // map value at index

console.log(op);

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