javascript - 基于多个标准对多维数组进行排序

Question

我正在尝试找出一种有效的方法来根据另一个数组存在的值的数量对多维数组进行排序。

给定以下数组: [1,2,3,4,5,6,7,8,9,10]

我正在尝试根据包含的值的数量对另一个数组进行排序。

[
  [1,3,5,7,9,22],
  [1,200,300,400,500,600],
  [1,2,3,4,5,6]
]

所以我试图访问的代码将返回:

[
  [1,2,3,4,5,6],
  [1,3,5,7,9,22],
  [1,200,300,400,500,600]
]

我认为我正在做的事情效率很低，可以用我不知道的方法写得更好或更简洁吗？

https://jsfiddle.net/gb3fsLdv/

const compareNums = [1,2,3,4,5,6,7,8,9,10];
let ourData = [
  [1,2,3,100,200,300],
  [100,200,300,400,500,600],
  [1,2,3,5,6,9]
];

function sortArr(compare, data){
  let indexMatches = [];
  data.map(arr => {
    let count = 0;
    compare.map(num => {
      if(arr.includes(num)){ 
        count++ 
        }
    })
    indexMatches.push(count);
  })
  // So now I have indexMatches with a count of how many hits each array has in the correct index order as the original data
  // And I can use data to sort them based on these values...
  // Little stuck how to relate the two so the same sorting happens to both arrays
}

sortArr(compareNums, ourData);

Answer 1

首先将给定的数组转换为集合。然后使用filter()获取其他数组中包含的元素数量

const data = [
  [1,3,5,7,9,22],
  [1,200,300,400,500,600],
  [1,2,3,4,5,6]
]

let arr = [1,2,3,4,5,6,7,8,9,10];

function getCount(arr, set){
  return arr.filter(x => set.has(x)).length
}
function sortOnCount(data, arr){
  let set = new Set(arr);
  return data.slice(0).sort((a, b) => getCount(b, set) - getCount(a, set))
}

console.log(sortOnCount(data, arr))