有没有一种方便的方法可以从这个数组中获取前 n 个索引:
var alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
并将其存储在另一个数组中，比如 alphabet2 = ['a','b','c']; 而不必使用循环进行暴力破解？谢谢
最佳答案
使用the slice method :
> var alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
> alphabet.slice(0,3)
["a", "b", "c"]
关于javascript - 在javascript中获取数组子索引的便捷方法，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11782265/