这是我正在做的。我在我创建的 gridview 的标题行中创建了两个按钮。按钮是 +page 和 -page。当 -page 被点击时，我删除了分页，所有数据都沿着页面向下移动，-page 消失，+page 在那里。
我的问题来了 当我点击 +page 时，我必须进行双重回发，因为我的一行数据消失了。我将在下面提供代码。我该怎么做才能解决这个问题？？
Dim bttnrempag As New Button
bttnrempag.ID = "bttnrempag"
bttnrempag.Text = " Paging"
bttnrempag.CssClass = "bttnMinEG"
bttnrempag.ValidationGroup = "alone"
bttnrempag.Attributes.Add("onclick", "return Paging('1')")
Dim bttnallowpag As New Button
bttnallowpag.ID = "bttnallowpag"
bttnallowpag.Text = " Paging"
bttnallowpag.ValidationGroup = "alone"
bttnallowpag.CssClass = "bttnAddEG"
bttnallowpag.Attributes.Add("onclick", "return Paging('0')")
--------------------按钮的添加方式---------------- ------------------------
Dim row As New GridViewRow(-1, -1, DataControlRowType.Separator, DataControlRowState.Normal)
row.Cells.Add(cell)
cell.Controls.Add(bttnrempag) '36
cell.Controls.Add(bttnallowpag)
-------------------------------------------- ------------------------------------------
function Paging(remove) {
var gridView = $get('<%=Gridview1.ClientID %>');
var txt2 = $get('<%=TextBox2.ClientID %>');
if (remove == '1') {
txt2.value = '1';
__doPostBack('<%=UpdatePanel1.ClientID %>', '');
return false;
}
else {
txt2.value = '0';
__doPostBack('<%=UpdatePanel1.ClientID %>', '');
return false;
}
已编辑
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate >
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
<asp:GridView ID="GridView1" runat="server" AllowPaging="True"
AutoGenerateColumns="False" BackColor="White" BorderColor="#E7E7FF"
BorderStyle="None" BorderWidth="1px" CellPadding="3"
DataSourceID="SqlDataSource1" Font-Names="Comic Sans MS" Font-Size="XX-Small"
Caption = '<table border="" width="100%" cellpadding="3" cellspacing="0" bgcolor="#4A3C8C"><tr><td style = "font-size:X-large;font-family:Arial CE;color:White"><b>Ordering/Receiving Log</u></td></tr></table>'
Font-Bold="True" PageSize="15" >
<RowStyle BackColor="#E7E7FF" ForeColor="#4A3C8C" />
<Columns>
Bound Data
</Columns>
<FooterStyle BackColor="#B5C7DE" ForeColor="#4A3C8C" />
<PagerStyle BackColor="#E7E7FF" ForeColor="#4A3C8C" HorizontalAlign="Right" />
<EmptyDataTemplate>
<head>
<meta http-equiv="refresh" content="5;URL=/Corporate_newpo/ReceivingLog.aspx?">
</head>
<script type="text/javascript" >
var count = 6;
var counter = setInterval("timer()", 1000); //1000 will run it every 1 second
function timer() {
count = count - 1;
if (count <= 0) {
clearInterval(counter);
//counter ended, do something here
return;
}
$get("timer").innerHTML = "The Table will Reload in " + count + " secs";
}
</script>
<asp:Label ID="Label1" runat="server" Font-Bold="True" Font-Size="Large"
ForeColor="#993333" Text="No Data was Found for the Selected Filter"></asp:Label><br /><br />
<span id="timer" style="font-size:medium;color:blue"></span>
</EmptyDataTemplate>
<SelectedRowStyle BackColor="#738A9C" Font-Bold="True" ForeColor="#F7F7F7" />
<HeaderStyle BackColor="#4A3C8C" Font-Bold="True" ForeColor="#F7F7F7" />
<AlternatingRowStyle BackColor="#F7F7F7" />
<PagerTemplate>
<small 12px""="" style="font-size:xx-small; padding-right">Go To Page</small>
<asp:DropDownList ID="ddlPageSelector" runat="server" AutoPostBack="true"
Font-Size="XX-Small" Height="19px" Width="36px">
</asp:DropDownList>
<asp:ImageButton ID="btnFirst" runat="server" CommandArgument="First"
CommandName="Page" SkinID="pagefirst" />
<asp:ImageButton ID="btnPrevious" runat="server" CommandArgument="Prev"
CommandName="Page" SkinID="pageprev" />
<asp:ImageButton ID="btnNext" runat="server" CommandArgument="Next"
CommandName="Page" SkinID="pagenext" />
<asp:ImageButton ID="btnLast" runat="server" CommandArgument="Last"
CommandName="Page" SkinID="pagelast" />
</PagerTemplate>
</asp:GridView>
</ContentTemplate>
</asp:UpdatePanel>
正如您所看到的，当一个或另一个被点击时，我将一个文本框设置为某个值，然后我对我的 Gridview 进行部分回发，它位于该 Updatepanel 中。
最佳答案
我怀疑这是因为您调用了“__doPostBack”方法。按钮的正常默认点击行为将执行异步回发，您可能让它在其他时间执行。尝试将其删除，看看效果如何。
关于c# - 停止双重回发，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1439312/