我正在尝试弄清楚如何将逗号 ,
分隔的列表作为输入传递,并让我的函数一次处理一个值。
我的功能:
addToWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
echo "${_ip}";
read -a arr <<<${_ip};
for i in ${arr[@]};
do
exp="db.account.update({\"account\":'${_account}'},{\$addToSet:{\"ip_list\": {\$each:['${_ip}'] }}})";
${_mongo} ${host}/${db} --eval "$exp"
done
}
我这样运行我的脚本:
./myscript.sh -m add -a pizzahut -i 123.456.790.007,123.456.790.008
我的代码进行中:
#!/usr/local/bin/bash
set -e
set -x
# Usage for getopts
usage () {
echo "Example: $0 -m find -a pizzahut"
echo "Example: $0 -m add -a pizzahut -i 10.10.123.456"
exit 1;
}
while getopts ":m:a:i:" o; do
case "${o}" in
m)
_mode=${OPTARG}
if [[ "${_mode}" != find && "${_mode}" != add ]]; then
usage
fi
;;
a)
_account=${OPTARG}
;;
i)
_ip=${OPTARG}
set -f
IFS=,
;;
*)
usage
;;
esac
done
shift $((OPTIND-1))
getWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
exp="db.account.find({\"account\":'${_account}'},{ip_list: 1}).pretty();";
${_mongo} ${host}/${db} --eval "$exp"
}
# Read a list
addToWhitelist ()
{
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo);
echo "${_ip}";
read -a arr <<<${_ip};
for i in ${arr[@]};
do
exp="db.account.update({\"account\":'${_account}'},{\$addToSet:{\"ip_list\": {\$each:['${_ip}'] }}})";
${_mongo} ${host}/${db} --eval "$exp"
done
}
case "${_mode}" in
'find')
echo "Finding information for the account ${_account}"
getWhitelist
;;
'add')
echo "Adding the following IP: ${_ip}"
addToWhitelist
;;
esac
set +x
但是,我在调用该函数时遇到的问题是将值作为单个字符串插入:
"ip_list" : [
"123.456.790.006",
"123.456.790.007,123.456.790.008",
"123.456.790.009"
]
}
期待:
"ip_list" : [
"123.456.790.006",
"123.456.790.007",
"123.456.790.008",
"123.456.790.009"
]
}
最佳答案
由于您的脚本接收到以逗号分隔的 IP 列表,因此实际上类似于:
_ip="123.456.790.007,123.456.790.008"
您需要按 ,
拆分列表,并在将每个 IP 提供给 Mongo 的 $each
运算符之前将其用引号引起来。
首先,将 IFS
的重新定义仅局限于 read
命令,然后利用 printf
重用相同格式字符串的行为,当更多提供参数(扩展数组 "${arr[@]}"
),通过 -v
选项将结果存储到变量,并去除前导 ,
从结果:
IFS=, read -a arr <<<"${_ip}"
printf -v ips ',"%s"' "${arr[@]}"
ips="${ips:1}"
对于上面给出的_ip
值,这个脚本将存储在ips
变量中:
"123.456.790.007","123.456.790.008"
因此,将此应用于您的程序,首先更改您的 i)
案例:
case "${o}" in
# ...
i) _ip=${OPTARG};;
esac
然后修复addToWhitelist
函数:
addToWhitelist() {
host='127.0.0.1'
db='mytest'
_mongo=$(which mongo)
IFS=, read -a arr <<<"${_ip}"
printf -v ips ',"%s"' "${arr[@]}"
ips="${ips:1}"
exp="db.account.update({'account': '${_account}'}, {\$addToSet:{'ip_list': {\$each:[$ips]}}})";
"${_mongo}" "${host}/${db}" --eval "$exp"
}
关于bash 脚本 - 如何将逗号分隔列表作为函数的输入参数进行处理,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46782689/