bash - 当文件中的字段匹配时，对 csv 中的多行求和

Question

我有一个文件，我已将其精简为如下所示:

"Reno","40.00"
"Reno","40.00"
"Reno","80.00"
"Reno","60.00"
"Lakewood","150.00"
"Altamonte Springs","50.25"
"Altamonte Springs","25.00"
"Altamonte Springs","25.00"
"Sandpoint","50.00"
"Lenoir City","987.00"

等等

我最终想要得到的是每个城市的总金额。即:

"Reno","220.00"
"Lakewood","150.00"
"Altamonte Springs","100.25"

等等

公平警告，数据集不一定是连续的——也就是说，一个城市可能在这里出现一次，向下一千行出现一次，最后还有 3 次。

我一直在尝试使用以下 awk 脚本:

awk -F "," '{array[$1]+=$2} END { for (i in array) {print i"," array[i]}}' test1.csv > test6.csv

我得到的结果如下所示:

"Matawan",0
"Bay Side",0
"Pataskala",0
"Dorothy",0
"Haymarket",0
"Myrtle Point",0

等等。第二列全为零，没有引号。

我显然遗漏了一些东西，但我不知道要看什么或在哪里看。我错过了什么？

谢谢。

Answer 1

你失败的原因是双引号。

做这样的事情:

sed 's/"//g' file.csv | awk -F "," '{array[$1]+=$2}END{for(i in array) {print "\""  i "\""  ","  "\"" array[i] "\"" }}' 

"Lenoir City","987"
"Reno","220"
"Lakewood","150"
"Sandpoint","50"
"Altamonte Springs","100.25"