bash - 将数据从一个来源迁移到另一个来源的脚本

Question

我有一个 .h 文件，其中包含这种格式的数据

struct X[]{
{"Field", "value1 value2 value"},
{"Field2", "value11 value12 value232"},
{"Field3", "x  y z"},
{"Field4", "a bbb s"},
{"Field5", "sfsd sdfdsf sdfs"};
/****************/
};

我有一个包含我想用新值替换 .h 文件中的值的文本文件

value1   Valuesdfdsf1  
value2   Value1dfsdf  
value3   Value1_another  
sfsd     sfsd_ewew   
sdfdsf   sdfdsf_ew 
sdfs     sfsd_new   

生成的 .h 文件将包含上述文本文件的替换内容。其他一切都保持不变。

struct X[]{
    {"Field1", "value11 value12 value232"},
    {"Field2", "value11 value12 value232"},
    {"Field3", "x  y z"},
    {"Field4", "a bbb s"},
    {"Field5", "sfsd_ewew sdfdsf_ew sdfs_new"};
    /****************/
    };

请帮助我提出一个使用 unix 工具完成它的解决方案:awk、perl、bash、sed 等

Answer 1

cat junk/n2.txt | perl -e '{use File::Slurp; my @r = File::Slurp::read_file("junk/n.txt"); my %r = map {chomp; (split(/\s+/,$_))[0,1]} @r; while (<>) { unless (/^\s*{"/) {print $_; next;}; my ($pre,$values,$post) = ($_ =~ /^(\s*{"[^"]+", ")([^"]+)(".*)$/); my @new_values = map { exists $r{$_} ? $r{$_}:$_ } split(/\s+/,$values); print $pre . join(" ",@new_values) . $post . "\n"; }}'     

结果:

struct X[]{
{"Field", "value1 Value1dfsdf value"},
{"Field2", "value11 value12 value232"},
{"Field3", "x y z"},
{"Field4", "a bbb s"},
{"Field5", "sfsd_ewew sdfdsf_ew sfsd_new"};
/****************/
};

解开代码:

use File::Slurp;
my @replacements = File::Slurp::read_file("junk/n.txt"); 
my %r = map {chomp; (split(/\s+/,$_))[0,1]} @replacements; 
while (<>) {
    unless (/^\s*{"/) {print $_; next;}
    my ($pre,$values,$post) = ($_ =~ /^(\s*{"[^"]+", ")([^"]+)(".*)$/); 
    my @new_values = map { exists $r{$_} ? $r{$_} : $_ } split(/\s+/, $values);
    print $pre . join(" ",@new_values) . $post . "\n";
}