bash 循环跳过注释行

Question

我正在遍历文件中的行。我只需要跳过以“#”开头的行。 我该怎么做？

 #!/bin/sh 

 while read line; do
    if ["$line doesn't start with #"];then
     echo "line";
    fi
 done < /tmp/myfile

感谢您的帮助!

Answer 1

while read line; do
  case "$line" in \#*) continue ;; esac
  ...
done < /tmp/my/input

然而，坦率地说，转向 grep 通常会更清楚:

grep -v '^#' < /tmp/myfile | { while read line; ...; done; }