rust - 无法分配给 `x`，因为它是借用的

Question

尝试将更多元素推送到向量时出现以下错误。如何克服这个错误

error[E0506]: cannot assign to `x` because it is borrowed

x = format!(r"\*START TIME*{:?}\S*\s+(?P<Value>[a-zA-Z0-9_\-\.]+)", ts);
   |         ^^ assignment to borrowed `x` occurs here
76 |         core_regex_dict.push(&x);
   |         ---------------      --- borrow of `x` occurs here
   |         |
   |         borrow later used here

代码:

let mut x = String::new();  
    for ts in test_list {
        x = format!(r"\*START TIME*{:?}\S*\s+(?P<Value>[a-zA-Z0-9_\-\.]+)", ts);
        core_regex_dict.push(&x);  
    }

Answer 1

很难回答您的问题，因为您没有提供足够的信息。特别是，我们需要知道如何 core_regex_dict被定义为。我假设 core_regex_dict类型为 Vec<&str> .您需要将其更改为 Vec<String> :

let core_regex_dict = Vec::new(); // No need to specify the item type, it will be inferred.
// No need to declare `x` before the loop unless you need to use the 
// last value afterward...
for ts in test_list {
    let x = format!(r"\*START TIME*{:?}\S*\s+(?P<Value>[a-zA-Z0-9_\-\.]+)", ts);
    core_regex_dict.push (x);  // No `&` -> we push the String itself instead of a reference
}