我正在接收传感器数据流,我需要汇总这些数据并对其执行基本统计(平均值、最大值、最小值等)。有多个值,但传感器数据可能不一致,并且某些值可能会丢失。
从阅读本书来看,当 luminosity
或 color
的值丢失时,似乎应该使用 Option
但我很困惑这个。
这是我的传感器数据的示例:
[
{
"sensor": "left",
"luminosity": "50",
"color": "(255,0,0)"
},
{
"sensor": "left",
"color": "#0f0"
},
{
"sensor": "right",
"luminosity": "20"
},
{
"sensor": "right",
"luminosity": "40",
"color": "(255,0,0)"
},
{
"sensor": "left",
"luminosity": "30"
},
{
"sensor": "top",
"luminosity": "10"
},
{
"sensor": "right",
"color": "(0,0,0)"
}
]
每个传感器的数据将存储在以下结构的实例中:
struct Data {
pub luminosity: Vec<String>,
pub color: Vec<String>,
}
我想迭代上面的 JSON 对象,将传感器与正确的结构实例匹配(“正确的”传感器与“正确的”传感器结构)并将每个 JSON 观察的内容推送到向量上(在每个结构实例中).
需要记录缺失值,以便对于每个“观察”,对应传感器的结构实例的结构中的每个向量都有一个推送操作。
最佳答案
像这样的东西应该可以工作。它使用 Serde将每个 JSON 数组元素读入具有所需传感器名称的辅助结构 String
, 和 Option<String>
传感器每个值的数据。然后它遍历这些读数并将它们插入到 map 中,其中键是传感器名称,值是每个传感器值的数据向量。
#[macro_use]
extern crate serde_derive;
extern crate serde;
extern crate serde_json;
use std::collections::BTreeMap as Map;
use std::error::Error;
#[derive(Debug, Default)]
struct Data {
luminosity: Vec<Option<String>>,
color: Vec<Option<String>>,
}
fn main() {
let input = r##"[
{
"sensor": "left",
"luminosity": "50",
"color": "(255,0,0)"
},
{
"sensor": "left",
"color": "#0f0"
},
{
"sensor": "right",
"luminosity": "20"
},
{
"sensor": "right",
"luminosity": "40",
"color": "(255,0,0)"
},
{
"sensor": "left",
"luminosity": "30"
},
{
"sensor": "top",
"luminosity": "10"
},
{
"sensor": "right",
"color": "(0,0,0)"
}
]"##;
let m = read_sensor_data(input).unwrap();
println!("{:#?}", m);
}
fn read_sensor_data(input: &str) -> Result<Map<String, Data>, Box<Error>> {
// Private helper struct that matches the format of the raw JSON
#[derive(Deserialize)]
struct RawReading {
sensor: String,
luminosity: Option<String>,
color: Option<String>,
}
// Deserialize the raw data
let raw_readings: Vec<RawReading> = serde_json::from_str(input)?;
// Loop over raw data and insert each reading into the right sensor's struct
let mut m = Map::new();
for raw in raw_readings {
// Look up this sensor's Data struct
let sensor = m.entry(raw.sensor).or_insert_with(Data::default);
// One push for every vector in the struct, even for missing observations
sensor.luminosity.push(raw.luminosity);
sensor.color.push(raw.color);
}
Ok(m)
}
关于json - 如何通过属性将 JSON 对象数组整理成包含每个对象属性向量的结构?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47245397/