我对 Rust 比较陌生,对 Serde 更是如此,所以我很难确定这是否可行。我有一个 JSON 文件,它对同一个键有两种不同的表示形式:
"coordinates": [
[
[
121.423364,
24.9913596
],
[
121.4233327,
24.9912977
],
]
]
还有这个:
"coordinates": [
[
121.4472492,
25.0052053
],
[
121.4466457,
25.0028547
]
]
同一个属性中有一个二维数组和一个三维数组表示方式。这使得文件难以序列化。
这是我实现的代码:
#[derive(Serialize, Deserialize, Debug)]
struct Geometry {
#[serde(deserialize_with = "string_or_number", rename = "type")]
geometry_type: Value,
#[serde(default, skip_serializing_if = "Vec::is_empty", rename = "coordinates")]
geometry_coor: Vec<Coordinates>,
#[serde(default, skip_serializing_if = "Vec::is_empty", rename = "coordinates")]
geometry_coor2: Vec<Vec<Coordinates>>,
}
#[derive(Serialize, Deserialize, Debug)]
struct Coordinates {
#[serde(deserialize_with = "string_or_number")]
longitude: Value,
#[serde(deserialize_with = "string_or_number")]
latitude: Value,
}
fn string_or_number<'de, D>(de: D) -> Result<Value, D::Error>
where
D: serde::Deserializer<'de>,
{
let helper: Value = Deserialize::deserialize(de)?;
match helper {
Value::Number(n) => {
println!("{:#?}", n.as_f64().unwrap().to_string());
Ok(Value::Number(n))
}
Value::String(s) => Ok(json!(s)),
_ => Ok(json!(null)),
}
}
我在序列化坐标文件的 struct Geometry
中遇到了麻烦。
有什么方法可以处理这种形式吗?
最佳答案
我得到了 help from the serde-rs developer :
I would recommend using an untagged enum to represent a coordinate array that can be 2d or 3d. Playground link
修改后的代码如下:
#[derive(Serialize, Deserialize, Debug)]
struct Geometry {
#[serde(deserialize_with = "string_or_number", rename = "type")]
geometry_type: Value,
#[serde(default, skip_serializing_if = "Vec::is_empty", rename = "coordinates")]
geometry_coor: Vec<Coordinates_form>,
}
#[derive(Serialize, Deserialize, Debug)]
#[serde(untagged)]
enum Coordinates_form {
#[serde(skip_serializing)]
OneD(Coordinates),
#[serde(skip_serializing)]
TwoD(Vec<Coordinates>),
#[serde(skip_serializing)]
ThreeD(Vec<Vec<Coordinates>>),
}
#[derive(Deserialize, Debug)]
struct Coordinates {
#[serde(deserialize_with = "string_or_number")]
longitude: Value,
#[serde(deserialize_with = "string_or_number")]
latitude: Value,
}
fn string_or_number<'de, D>(de: D) -> Result<Value, D::Error>
where
D: serde::Deserializer<'de>,
{
let helper: Value = Deserialize::deserialize(de)?;
match helper {
Value::Number(n) => {
println!("{:#?}", n.as_f64().unwrap().to_string());
Ok(Value::Number(n))
}
Value::String(s) => Ok(json!(s)),
_ => Ok(json!(null)),
}
}
关于json - 在同一属性中解析具有多种表示形式的 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51890312/