mysql - 如何从值不是...的 mysql 表中进行选择？

Question

输入:

$result = $db->query('SELECT * 
         FROM data 
         ')->fetchAll(PDO::FETCH_ASSOC);

结果:

id    name   status
1     dog    ok
2     frog

输入:

 $result = $db->query('SELECT * 
             FROM data 
             WHERE status = `ok`
             ')->fetchAll(PDO::FETCH_ASSOC);

结果:

id    name   status
1     dog    ok

输入:

 $result = $db->query('SELECT * 
             FROM data 
             WHERE status != `ok`
             ')->fetchAll(PDO::FETCH_ASSOC);

结果:

id    name   status

输入:

 $result = $db->query('SELECT * 
             FROM data 
             WHERE status <> `ok`
             ')->fetchAll(PDO::FETCH_ASSOC);

结果:

id    name   status

我希望得到的结果是 WHERE status is NOT ok

id    name   status
2     frog

Answer 1

试试这个...

$result = $db->query("SELECT * FROM data WHERE status <> 'ok' ")->fetchAll(PDO::FETCH_ASSOC); 

或者如果您要查找状态为空的行，请尝试...

$result = $db->query("SELECT * FROM data WHERE status = '' ")->fetchAll(PDO::FETCH_ASSOC); 

如果您想使用单引号，请使用以下内容:

$result = $db->query('SELECT * FROM data WHERE status <> \'ok\' ')->fetchAll(PDO::FETCH_ASSOC); 

注意引号用斜线转义。