python - 将元组转换为日期时间

Question

我想将日期和时间保存到 mysql 表中，并在以后使用它们。如何将元组转换为日期时间以使用此值？

from datetime import datetime, timedelta
import mysql.connector

mydb = mysql.connector.connect(
  host="localhost",
  user="**USER**",
  passwd="**PASSWORT**",
  database="**DATABASE"**
)

# Table already created like this:
# mycursor.execute("CREATE TABLE events2 (id INT AUTO_INCREMENT PRIMARYKEY, name VARCHAR(255), startdate DATETIME, enddate DATETIME, deadline INT, position INT, reminder INT)")

name = "Testevent"
startdate = datetime.now().strftime('%Y-%m-%d %H:%M:%S')
enddate = datetime.now() + timedelta(days=14)
deadline = 24
position = 25
reminder = 1

sql = "INSERT INTO events2 (name, startdate, enddate, deadline, position, reminder) VALUES (%s, %s, %s, %s, %s, %s)"
val = (name, startdate, enddate, deadline, position, reminder)
mycursor.execute(sql, val)
mydb.commit()

mycursor = mydb.cursor()

mycursor.execute("SELECT startdate FROM events2 WHERE id = '7'")

myresult = mycursor.fetchone()

print(myresult)
y = myresult + timedelta(days=14)

输出:

(datetime.datetime(2018, 8, 20, 18, 31, 42),)
Traceback (most recent call last):
  File ".../Create_event.py", line 54, in <module>
    y = myresult + timedelta(days=14)
TypeError: can only concatenate tuple (not "datetime.timedelta") to tuple

Answer 1

myresult 是一个包含一个对象的元组:datetime.datetime。然后你必须做:

y = myresult[0] + timedelta(days=14)

由于您的 print，这很容易被注意到，我们看到 datetime 对象包含在一个元组中(语法为 (elem1, [elem2, ...]))