请帮我加入这两个选择:
SELECT IFNULL(sum(estimated_hours * t2.man_hour),0) as
estimated from project_has_tasks t1 left join users t2
on t1.user_id = t2.id group by project_id
SELECT IFNULL(sum(TIME_FORMAT(SEC_TO_TIME
(time_spent),'%k.%i' )* t2.man_hour),0) as time_spent_cost FROM project_has_tasks t1
left join users t2 on t1.user_id = t2.id group
by project_id
想要得到:
| estimated | time_spent_cost |
_______________________________
| 000000000 | 00000000 |
最佳答案
只需将它们放在一个查询中:
SELECT IFNULL(sum(estimated_hours * t2.man_hour),0) as
estimated, IFNULL(sum(TIME_FORMAT(SEC_TO_TIME
(time_spent),'%k.%i' )* t2.man_hour),0) as time_spent_cost
from project_has_tasks t1 left join users t2
on t1.user_id = t2.id group by project_id
关于mysql - 在 SELECT [MYSQL] 中加入或选择，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/52330053/