我有以下简单表格,您也可以在 SQL Fiddle
中找到它 here :
CREATE TABLE Orders (
Customer TEXT,
Order_Date DATE
);
INSERT INTO Orders
(Customer, Order_Date)
VALUES
("Customer A", "2017-05-23"),
("Customer B", "2018-09-10"),
("Customer B", "2018-12-14"),
("Customer A", "2019-01-03"),
("Customer A", "2019-02-15"),
("Customer C", "2017-09-04"),
("Customer B", "2019-01-09"),
("Customer A", "2019-02-16"),
("Customer C", "2019-02-12"),
("Customer B", "2018-01-03");
如您所见,表格显示了不同客户的订单日期。
我使用以下 SQL 获取在 2019 年 2 月下订单的所有客户:
SELECT Customer
FROM ORDERS
WHERE Order_Date >= "2019-02-01 00:00:00"
AND Order_Date < "2019-03-01 00:00:00"
到目前为止一切正常。
但是,现在我想实现只列出客户
a) 2 月 下订单
WHERE order in >= "2019-02-01 00:00:00" AND < "2018-03-01 00:00:00"
b) 没有在 12 个月前下订单,并且
WHERE no order < "2019-02-01 00:00:00" AND >= "2018-01-02 00:00:00"
c) 在此 12 个月期限之前下了订单
WHERE order in < "2018-01-02 00:00:00"
我需要在查询中更改什么才能实现此目的?
最佳答案
这有点复杂,但是您可以使用group by
和having
:
SELECT o.Customer
FROM ORDERS o
GROUP BY o.Customer
HAVING SUM( o.Order_Date >= '2019-02-01' AND o.Order_Date < '2019-03-01' ) > 0 AND
SUM( o.Order_Date >= '2018-01-02' AND o.Order_Date < '2019-02-01' ) = 0 AND
SUM( o.Order_Date < '2018-01-02' ) > 0 ;
关于mysql - 选择某个时间段之前和之后存在的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54872070/