SELECT
1+(SELECT count(*) from games a WHERE a.score > g.score) as rank,
score, p.leaderboard_initials, p.operating_system
FROM games g
inner join players p on (p.google_id = g.google_id)
ORDER BY score DESC
LIMIT 0, 100;
返回一个排行榜,其中包含玩家的每场比赛。
我需要返回一个排行榜,其中只列出了每个玩家的最佳得分游戏。所以 44rhh
仍将排在首位,其次是 DMC
,但 BMO
将排在第三位。
我知道解决方案应该很简单,但我就是想不出该怎么做!
最佳答案
您可以按 leaderboard_initials 选择最高分组
您可以按 leaderboard_initials 选择最高分组
set @rank=0;
select (@rank:=@rank+1) rank , leaderboard_initials, max(score) max_score
from (
SELECT
1+(SELECT count(*)
from games a WHERE a.score > g.score) as rank,
score, p.leaderboard_initials, p.operating_system
FROM games g
inner join players p on (p.google_id = g.google_id)
ORDER BY score DESC
LIMIT 0, 100;
) t
group by leaderboard_initials
order by max_score DESC
关于mysql - 我的 MySQL 查询如何给出所有游戏的排名只给出每个玩家顶级游戏的排名?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55381562/