mysql选择其中一条有n项的记录

Question

如果其中 1 条记录包含 n，我将尝试获取所有记录，因此如果我有 3 条记录并且其中任何一条记录的 disposition_id = 1 并且它们的 time_spent 总和为 20 或更多并且属于同一个 patient_id

Table: Transactions
+----+------------+----------------+------------+------------+
| id | patient_id | disposition_id | time_spent | created_at |
+----+------------+----------------+------------+------------+
| 1  | 10         |             25 |         10 |      NOW() |
+----+------------+----------------+------------+------------+
| 2  | 10         |              1 |          2 |      NOW() |
+----+------------+----------------+------------+------------+
| 3  | 10         |             12 |          9 |      NOW() |
+----+------------+----------------+------------+------------+
| 4  | 12         |              1 |          8 |      NOW() |
+----+------------+----------------+------------+------------+

预期结果

Table: Transactions
+------------+------------+
| patient_id | time_spent |
+------------+------------+
| 10         |         21 |
+------------+------------+

即使 disposition_id 为 1，patient_id 为 12 也不会显示，它没有花费 20 或更多时间。但 patient_id 10 确实两者都有。

到目前为止我的查询是:

SELECT t.patient_id, t.disposition_id AS did, SUM(t.time_spent) AS sum_time
FROM transactions AS t
WHERE
    YEAR(t.created_at) = YEAR(CURDATE()) AND MONTH(t.created_at) = MONTH(CURDATE())
GROUP BY
    t.patient_id
HAVING sum_time >= 20

我尝试在 where 和 having 子句中使用 IN (1, t.disposition_id)，但返回了 0 条记录。我觉得我很接近，但似乎无法将它们放在一起。

Answer 1

按 patient_id 聚合，然后断言您的两个要求:

SELECT
    t.patient_id,
    SUM(t.time_spent) AS sum_time
FROM transactions t
WHERE
    YEAR(t.created_at) = YEAR(CURDATE()) AND MONTH(t.created_at) = MONTH(CURDATE())
GROUP BY
    t.patient_id
HAVING
    COUNT(CASE WHEN t.disposition_id = 1 THEN 1 END) > 0 AND
    SUM(t.time_spent) > 20;