我正在尝试使用以下代码使用 UNION ALL 将多个表数据提取到 high-chart，但我无法做到这一点。
<?php
require_once("db.php");
$db->beginTransaction();
try{
$query = "SELECT SUM(marks) AS marks, DATE(date_column) AS daTe, 'class 1' AS class FROM table1 Group By DATE(date_column)
UNION ALL
SELECT SUM(marks) AS marks, DATE(date_column) AS daTe, 'class 2' AS class FROM table2 Group By DATE(date_column)
UNION ALL
SELECT SUM(marks) AS marks, DATE(date_column) AS daTe, 'class 3' AS class FROM table3 Group By DATE(date_column)";
$done= $db->prepare($query);
$done->execute();
$display = '';
$row = $done->fetch()
$result[] = $row;
//$display .="{name:".$row->class.", data:".$row->marks.", date:".$row->daTe."},";
$db->commit();
}
catch(PDOException $e){
echo 'Connection failed: ' . $e->getMessage();
}
Table 1 (class 1)
Table 2 (class 2)
Table 3 (class 3)
我已经更改了您的查询以获得所需的输出。结果将如下表所示。
查询给出如下结果。
<?php
require_once("db.php");
$db->beginTransaction();
try{
$query = "SELECT dr.dates, SUM(a.marks) AS t1marks, SUM(b.marks) AS t2marks, SUM(c.marks) AS t3marks FROM
(SELECT DISTINCT(DATE(date_column)) AS dates FROM `table1`
UNION
SELECT DISTINCT(DATE(date_column)) FROM `table2`
UNION
SELECT DISTINCT(DATE(date_column)) FROM `table3`) AS dr
LEFT JOIN table1 AS a ON dr.dates = DATE(a.date_column)
LEFT JOIN table2 AS b ON dr.dates = DATE(b.date_column)
LEFT JOIN table3 AS c ON dr.dates = DATE(c.date_column)
GROUP BY dr.dates ORDER BY dates ASC";
$done= $db->prepare($query);
$done->execute();
$rows = $done->fetchAll(PDO::FETCH_ASSOC);
$dates = $t1marks = $t2marks = $t3marks = array();
foreach ($rows as $row) {
$dates[] = $row['dates'];
$t1marks[] = $row['t1marks'] == null ? 0 : (int) $row['t1marks'];
$t2marks[] = $row['t2marks'] == null ? 0 : (int) $row['t2marks'];
$t3marks[] = $row['t3marks'] == null ? 0 : (int) $row['t3marks'];
}
$output = json_encode( array( array( 'data' => $t1marks, 'name' => 'class 1'),
array( 'data' => $t2marks, 'name' => 'class 2'),
array( 'data' => $t3marks, 'name' => 'class 3')
) );
$db->commit();
}
catch(PDOException $e){
echo 'Connection failed: ' . $e->getMessage();
}
?>
<!DOCTYPE html>
<html>
<body>
<div id="container" style="height: 370px; width: 100%;"></div>
<script src="https://code.highcharts.com/highcharts.js"></script>
<script src="https://code.highcharts.com/modules/series-label.js"></script>
<script src="https://code.highcharts.com/modules/exporting.js"></script>
<script src="https://code.highcharts.com/modules/export-data.js"></script>
<script>
Highcharts.chart('container', {
title: {
text: 'Solar Employment Growth by Sector, 2010-2016'
},
subtitle: {
text: 'Source: thesolarfoundation.com'
},
yAxis: {
title: {
text: 'Number of Employees'
}
},
xAxis: { categories: <?php echo json_encode($dates); ?> },
legend: {
layout: 'vertical',
align: 'right',
verticalAlign: 'middle'
},
plotOptions: {
line: {
dataLabels: {
enabled: true
},
enableMouseTracking: false
}
},
series: <?php echo $output; ?>,
responsive: {
rules: [{
condition: {
maxWidth: 500
},
chartOptions: {
legend: {
layout: 'horizontal',
align: 'center',
verticalAlign: 'bottom'
}
}
}]
}
});
</script>
</body>
</html>
根据 fiddle ，以下数组中的以下元素不应匹配。
我们可以为不匹配的列元素添加 null 或零。在这里我添加了 0 以获得优雅的图形外观。其他明智的路线将打破值(value)观之间。
根据您的输入输出图表..
