我有两个表 insert1
和 received1
在 insert1 表中有列,列名是 recharge_account
。
received 表只有一列,列名是received_amount
。
我想将 recharge_ammount - total received_amount
作为会费。
recharge_Account Received_Amount dues
500 - 400 100
SELECT
SUM(Account_recharge) AS `Total Recharge`,
SUM(Amount_Received) AS `Total Received`,
SUM(Account_recharge) - SUM(Amount_Received) AS dues
FROM insert1 i1
INNER JOIN received1 r1
我无法准确计算。
最佳答案
您只需要一个连接条件,例如 ON i1.id = r1.ins_id
,以及针对空值的 COALESCE()
函数:
SELECT
SUM(COALESCE(Account_recharge,0)) AS `Total Recharge`,
SUM(COALESCE(Amount_Received,0)) AS `Total Received`,
SUM(COALESCE(Account_recharge,0)) - SUM(COALESCE(Amount_Received,0)) AS dues
FROM insert1 i1
JOIN received1 r1 ON i1.id = r1.ins_id
关于mysql - 添加一些列并减去另一列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57969514/