php - MySQL 和 PHP - 每个？

Question

我有以下代码:

SELECT q21, q21coding  AS Description FROM `tresults_acme` WHERE q21 IS NOT NULL AND q21 <> '' ORDER BY q21coding

它带回了以下内容(摘录):

Text                                                     Description
Lack of up to date equal pay cases&legislation - t... Content needs updating
The intranet could contain more "up to date traini... Content needs updating
Poorly set out. It is hard to find things.            Difficulty in navigating/finding content
Only use the intranet as a necessity. Will ask my ... Difficulty in navigating/finding content

现在，我想在 PHP 页面的表格中显示它，但由于我希望它的显示方式而遇到一些问题，它需要如下所示:

Content needs updating
----------------------
[List all the comments relating to this description]

Difficulty in navigating/finding content
----------------------------------------
[List all the comments relating to this description]

等等。

现在我认为这是 PHP 中的 For Each 循环，但我很难理解这个问题 - 非常非常欢迎任何想法和建议!

谢谢，

Answer 1

简单方法

1. 设置prev_desc至 NULL
2. 对于每一行打印text
3. 如果description不等于 prev_desc在新“部分”的描述前添加并设置 prev_desc <- description

例如¹(未经测试!)，

$prev_desc = null;
while ($row = mysql_fetch_assoc(...)) {
    if ($prev_desc != $row['description']) {
        print '<h1>' . $row['description'] . '</h1>';
        $prev_desc = $row['description'];
    }
    print $row['text'] . '<br />'; // Formatting needed
}

注意:您必须保留 ORDER BY <description-column>为了让行“分组”。否则这种简单的方法将行不通。

较少特定于演示文稿的方法

我可以被认为更“干净”来创建某种二维容器来“分类”提取的数据，例如，

$items = array(
    'Content needs updating' => array(
        'Lack of ...',
        'The intra...'
    ),
    ...
);

然后您可以像这样遍历这些项目¹:

foreach ($items as $desc => $texts) {
    print '<h1>' . $desc . '</h1>';
    foreach ($texts as $text) {
        print $text . '<br />';
    }
}

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¹ 正如@bobince 所指出的，确保直接进入最终 HTML 的内容被正确转义，参见例如 htmlspecialchars() .