我需要帮助将来自 MySQL 的数据与 PHP 结合起来并在同一个表中显示。
现在我明白了:
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 28 | Salad | 4 | 10.99|
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 28 | Pizza | 1 | 15 |
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 26 | Fish | 3 | 12 |
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 22 | Pizza | 1 | 15 |
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 22 | Salad | 1 | 10.99|
--------------------------------------
我想这样显示:
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 28 | Salad | 4 | 10.99|
| 28 | Pizza | 1 | 15 |
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 26 | Fish | 3 | 12 |
--------------------------------------
--------------------------------------
|Order ID | Product | Quantity| Cost |
--------------------------------------
| 22 | Pizza | 1 | 15 |
| 22 | Salad | 1 | 10.99|
--------------------------------------
我的 PHP 代码:
$username2= $_SESSION['Username'];
$result = mysql_query("SELECT * FROM order_detail, products WHERE order_detail.user = '$username2' AND order_detail.productid = products.serial ORDER BY orderid DESC");
while($row = mysql_fetch_array($result))
{
echo "<table class='curvedEdges'>
<tr>
<th>Order ID</th>
<th>Product</th>
<th>Quantity</th>
<th>Cost</th>
</tr>";
echo "<tr>";
echo "<td>" . $row['orderid'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['quantity'] . "</td>";
echo "<td>" . $row['price'] . " LT</td>";
echo "</tr>";
}
echo "</table>";
}
在 PHP 中执行此操作的最简单方法是什么?也许有人可以告诉我代码? :) 谢谢!
最佳答案
像这样的东西应该可以工作:
$orderID = null;
$tableShown = false;
while($row = mysql_fetch_array($result)) {
if ($orderID != $row['orderid']) {
if ($tableShown)
echo "</table>";
echo "<table class='curvedEdges'>
<tr>
<th>Order ID</th>
<th>Product</th>
<th>Quantity</th>
<th>Cost</th>
</tr>";
$tableShown = true;
}
echo "<tr>";
echo "<td>" . $row['orderid'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['quantity'] . "</td>";
echo "<td>" . $row['price'] . " LT</td>";
echo "</tr>";
$orderID = $row['orderid'];
}
if ($tableShown)
echo "</table>";
这会导致 HTML table
重新创建,其中包含订单 ID 中每次更改的 header 。
关于php - 合并表中相同 ID 的数据。,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16654990/