dictionary - 在单个语句中初始化 Go map

Question

这是我的代码:

var keys map[int]string
keys = make(map[int]string)

keys[1] = "aa"
keys[2] = "ab"
keys[3] = "ac"
keys[4] = "ba"
keys[5] = "bb"
keys[6] = "bc"
keys[7] = "ca"
keys[8] = "cb"
keys[9] = "cc"

我可以在一个语句和/或一行中做同样的事情吗？

Answer 1

是的，您可以使用单个语句创建 map (在规范中称为 composite literal):

var keys = map[int]string{
    1: "aa",
    2: "ab",
    3: "ac",
    4: "ba",
    5: "bb",
    6: "bc",
    7: "ca",
    8: "cb",
    9: "cc",
}

或者，如果你在函数内部，你可以使用 short variable declaration :

keys := map[int]string{
    1: "aa",
    2: "ab",
    3: "ac",
    4: "ba",
    5: "bb",
    6: "bc",
    7: "ca",
    8: "cb",
    9: "cc",
}