这里我创建了一个表http://jsbin.com/OJAnaji/13/edit和演示:http://jsbin.com/OJAnaji/13
因此,当用户单击表中的某些行时,会自动将表中的值填充到模式窗口中的输入字段中。单击“编辑行”按钮时用户打开模态窗口。现在我需要知道如何更新 mysql 表的列:姓名、性别、年龄、吃的 donut 。
我创建js ajax:
$("#edit").click(function() {
//in here we can do the ajax after validating the field isn't empty.
if($("#name").val()!="") {
$.ajax({
url: "update.php",
type: "POST",
async: true,
data: { Name:$("#name").val(), Gender:$("#gender").val(), Age:$("#age").val(), Donuts_eaten:$("#donuts_eaten").val()}, //your form data to post goes here as a json object
dataType: "html",
success: function(data) {
$('#output').html(data);
drawVisualization();
},
});
} else {
//notify the user they need to enter data
}
});
HTML - 模式窗口和按钮:
<!-- Button trigger modal -->
<button id="edit" class="btn btn-success disabled" type="button" data-toggle="modal" data-target="#myModal">
Edit selected row</button>
<!-- Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title" id="myModalLabel">Add new row</h4>
</div>
<div class="modal-body">
<div class="input-group">
<span class="input-group-addon">Name</span>
<input type="text" value="" id="name" class="form-control" placeholder="Type name">
</div></br>
<div class="input-group">
<span class="input-group-addon">Gender</span>
<input type="text" id="gender" class="form-control" placeholder="Gender?">
</div></br>
<div class="input-group">
<span class="input-group-addon">Age</span>
<input type="text" id="age" class="form-control" placeholder="Number of age">
</div></br>
<div class="input-group">
<span class="input-group-addon">Donuts eaten</span>
<input type="text" id="donuts_eaten" class="form-control" placeholder="Number of donuts eaten">
</div></br>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary">Save changes</button>
</div>
</div><!-- /.modal-content -->
</div><!-- /.modal-dialog -->
</div><!-- /.modal -->
那么我现在如何使用 php 更新 MySql 数据库:
so 文件 update.php 必须如下所示:
<?php
$con = mysql_connect('localhost', 'gmaestro_agro', 'pass') or die('Error connecting to server');
mysql_select_db('gmaestro_agro', $con);
//HOW I CAN UPDATE MYSQL DATABASE, WHAT I NEED TO ADD HERE?
?>
最佳答案
表中应该有一个自动递增列,例如“id”或像下面的示例一样使用“index_id”。这应该在创建表单时使用,并与 $_POST 数组一起发送以引用您正在更新的行。这是一个简单的示例,您可以使用它来入门。
$_POST = stripslashes_deep($_POST); # you will want to better filtering for security.
if(isset($_POST['Name']) && $_POST('Name') !=''){
$query = "UPDATE stat
SET Name ='". $_POST['Name'] . "',
Gender ='". $_POST['Gender'] . "',
Age ='". $_POST['Age'] . "',
Donuts_eaten ='" .$_POST['Donuts_eaten'] . "'
WHERE
index_id = '". $_POST['index_id'] . "'";
$result = mysql_query($query) or die(mysql_error());
exit(json_encode($_POST));
}
function stripslashes_deep($value)
{
$value = is_array($value) ?
array_map('stripslashes_deep', $value) :
stripslashes($value);
return $value;
}
对于您的 MYSQL 表,您可以在 MYSQL PhpMyAdmin 中运行此命令:
ALTER TABLE `stats` ADD `index_id` INT( 3 ) NOT NULL AUTO_INCREMENT FIRST ,
ADD PRIMARY KEY ( `index_id` )
关于javascript - 使用ajax使用php更新mysql表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21531193/