<分区>
可能重复，但我在这个上浪费了几个小时
$stmt=$mysql->prepare(" insert into test_booked_tickets(book_id, ticket_id, num_people) values(:book_id,:ticket_id,:num)");
echo (int)$ticket->id."<br/>";
echo (int)$ticket->number_people."<br/>";
echo (int)$booking->id."<br/>";
$stmt->bindValue(":ticket_id", (int)$ticket->id);
$stmt->bindValue(":num", (int)$ticket->number_people);
$stmt->bindValue(":book_id", (int)$booking->id);
try{
$stmt->execute();
}
catch(PDOException $e){
echo "catched <br/>";
echo $e->errorInfo;
}
其他查询完美运行。这些是 echo 的返回值
30
1
10
它不会陷入困境，也不会插入表中...