我正在尝试从我的 sql 中获取成员(member)照片并显示为幻灯片。我正在尝试使用 DHTML 幻灯片脚本 - © Dynamic Drive DHTML 代码库 (www.dynamicdrive.com) 在此处查看基本代码 basic code
现在我更改代码以使用 php 从 mysql 获取图像 url
我的代码:
Here is the html and script code.
<html>
<head>
<script type="text/javascript">
/***********************************************
* DHTML slideshow script- © Dynamic Drive DHTML code library (www.dynamicdrive.com)
* This notice must stay intact for legal use
* Visit http://www.dynamicdrive.com/ for full source code
***********************************************/
var photos = new Array()
<?php
$mid=$_POST['mid'];
//echo $mid;
$mid=$_POST['mid'];
require_once("datacon.php");
$result = $data->query("SELECT * FROM tempregist where id= $mid ");
$row = mysqli_fetch_array($result) or die(mysqli_error());
$folde= "uploads/thumb/";
$folder=utf8_encode($folde);
//echo $folder;
$mid1 =$row['mid'];
require_once("datacon.php");
$result = $data->query("SELECT image_name FROM tbl_images where mid= '$mid1' ");
$phparray = array();
$count = mysqli_num_rows($result);
if($count>=1)
{
while($crow = mysqli_fetch_array($result))
{
$i=0;
$phparray[$i] = $folder. $crow['image_name'];
$i++;
?>
photos<?php echo"[".$i."]" ;?> = <?php echo '"'. implode( $phparray) . '"'."\n" ;
} }
?>
var photoslink = new array
var x
x =<?php echo json_encode($count) ?>;
var which=0
/
//Specify whether images should be linked or not (1=linked)
var linkornot=0
Set corresponding URLs for above images. Define ONLY if variable linkornot equals "1"
photoslink[0]=""
photoslink[1]=""
photoslink[2]=""
//do NOT edit pass this line
var preloadedimages=new Array()
for (i=0;i<photos.length;i++){
preloadedimages[i]=new Image()
preloadedimages[i].src=photos[i]
}
function applyeffect(){
if (document.all && photoslider.filters){
photoslider.filters.revealTrans.Transition=Math.floor(Math.random()*23)
photoslider.filters.revealTrans.stop()
photoslider.filters.revealTrans.apply()
}
}
function playeffect(){
if (document.all && photoslider.filters)
photoslider.filters.revealTrans.play()
}
function keeptrack(){
window.status="Image "+(which+1)+" of "+photos.length
}
function backward(){
if (which>0){
which--
applyeffect()
document.images.photoslider.src=photos[which]
playeffect()
keeptrack()
}
}
function forward(){
if (which<photos.length-1){
which++
applyeffect()
document.images.photoslider.src=photos[which]
playeffect()
keeptrack()
}
}
function transport(){
window.location=photoslink[which]
}
</script>
</head>
<body>
<div align="center">
<img src="images/logo.jpg" border = "2" align="center" alt="no logo">
</div>
<table border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="100%" colspan="2" height="22"><center>
<script>
if (linkornot==1)
document.write('<a href="javascript:transport()">')
document.write('<img src="'+photos[0]+'" name="photoslider" style="filter:revealTrans(duration=2,transition=23)" border=0>')
if (linkornot==1)
document.write('</a>')
</script>
</center></td>
</tr>
<tr>
<td width="50%" height="21"><p align="left"><a href="#" onClick="backward();return false">Previous Slide</a></td>
<td width="50%" height="21"><p align="right"><a href="#" onClick="forward();return false">Next Slide</a></td>
</tr>
</table>
<p align="center"><font face="Arial" size="-2">Free DHTML scripts provided by<br>
<a href="http://dynamicdrive.com">Dynamic Drive</a></font></p>
</body>
</html>
现在我要出局如下 var photos = new Array()
photos[0] = "uploads/thumb/220816_1412135472.jpeg"
photos[0] = "uploads/thumb/312840_1412135511.jpeg"
photos[0] = "uploads/thumb/589453_1412135511.jpeg"
photos[0] = "uploads/thumb/467341_1412135630.jpeg"
photos[0] = "uploads/thumb/800658_1412135790.jpeg"
photos[0] = "uploads/thumb/366793_1412135826.jpeg"
但是我需要这样的输出
photos[0] = "uploads/thumb/220816_1412135472.jpeg"
photos[1] = "uploads/thumb/312840_1412135511.jpeg"
photos[2] = "uploads/thumb/589453_1412135511.jpeg"
photos[3] = "uploads/thumb/467341_1412135630.jpeg"
photos[4] = "uploads/thumb/800658_1412135790.jpeg"
photos[5] = "uploads/thumb/366793_1412135826.jpeg"
我试了很多。请任何人帮忙。
最佳答案
while($crow = mysqli_fetch_array($result))
{
$i=0;
你正在循环中重置 $i
关于javascript - 使用 javascript 使用 php 变量的幻灯片放映，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26279579/