php - 行成列查询 MySql

Question

我有这张表:

ID   CODE   WEEK  SEX
1    abc    1     F
2    abc    2     M
3    xyz    3     F
4    abc    1     M

我正在使用这个查询来过滤数据:

SELECT `code`,`week`,`sex`, COUNT(`week`) as cnt 
FROM `table` 
WHERE `code` = "abc" 
and `sex` = "F" 
group by `week` 
having (`week` > 0) 
UNION ALL 
SELECT `code`,`week`,`sex`, COUNT(`week`) as cnt 
FROM `table` 
WHERE `code` = "abc" 
and `sex` = "M"
group by `week` 
having (`week` > 0)

这是结果:

CODE   WEEK   SEX  cnt
abc    1      F    1
abc    1      M    1
abc    2      M    1

但现在我需要以这种方式显示数据:

CODE   WEEK  M  F
abc    1     1  1
abc    2     1  0

所以我有这个查询:

SELECT  
`WEEK`,`CODE`,  
GROUP_CONCAT(if(`SEX` = "F", `cnt`, NULL)) AS "F", 
GROUP_CONCAT(if(`SEX` = "M", `cnt`, NULL)) AS "M" 
FROM `temp_table`
GROUP BY `WEEK` 
ORDER BY CAST(`WEEK` AS UNSIGNED)

如何组合这 2 个查询？有一个更好的方法吗？

Answer 1

SELECT `WEEK`,`CODE`
, SUM(IF(`SEX` = "F", cnt, 0)) AS `F`
, SUM(IF(`SEX` = "M", cnt, 0)) AS `M`
FROM `table`
GROUP BY `WEEK`,`CODE`
;

我不确定您为什么要执行那个奇怪的 ORDER BY，而且我很确定您也想在 CODE 上分组。 (编辑:是的，CAST 适合星期的数据类型。)

如果使用第一个查询作为“来源”，请参见下文:

SELECT `WEEK`,`CODE`
, SUM(IF(`SEX` = "F", 1, 0)) AS `F`
, SUM(IF(`SEX` = "M", 1, 0)) AS `M`
FROM ([original query goes in here]) `subQ`
GROUP BY `WEEK`,`CODE`
;