php - 根据值显示数据库字段名称

Question

我有这样的数据库: The database is have same value (matthew) but in different fields

我想使用 HTML 和 PHP 制作一个搜索框，当我输入“matthew”时，它显示如下: when i search 'matthew' it's show like this

我的问题是使用什么查询来选择此值并显示“matthew”值所在的字段名称？

这是我的小代码:

<?php
$search='matthew';
$sql = mysql_query("select * from test where test.field_1 like '%$search%' or test.field_2 like '%$search%' or test.field_3 like '%$search%' order by id");
?>

<table width="200" border="1">
  <tr>
    <td align="center"><b>Name</b></td>
    <td align="center"><b>Field</b></td>
  </tr>
<?php
while ($data=mysql_fetch_array($sql))

{ ?>  
  <tr>
    <td align="center"><?php echo $data['name']; ?></td>
    <td align="center">&nbsp;</td>
  </tr>
<?php } ?>
</table>

但我不知道如何显示值所在的字段名称。

Answer 1

使用评论中的代码(尽管我建议使用 PDO，因为 mysql_* 已被弃用且不安全)

$sql = mysql_query("select * from test where test.field_1 like '%$search%' or test.field_2 like '%$search%' or test.field_3 like '%$search%'");

// i don't remember how fetching works in mysql_, i think something like this..
$results = mysql_fetch_assoc($sql);

foreach($results as $column_name => $value){
    // check for the string
    if(strpos($value, "mike") === false) continue; // or whatever, use the variable that contains the searched text instead of "mike"

    echo "result was found in the $column_name column. The full value of that column is $value";
}