我正在编写脚本以在错误跟踪系统中添加错误报告。 而点击提交按钮后，弹出SQL语法错误对话框。
这是我的代码
public partial class AddBugForm : Form
{
public AddBugForm()
{
InitializeComponent();
Fillcombo();
Fillcombo1();
Fillcombo2();
}
void Fillcombo()
{
string constring = "datasource = localhost; username = root; password = ";
string Query = "select * from bug.type";
MySqlConnection conDataBase = new MySqlConnection(constring);
MySqlCommand cmdDataBase = new MySqlCommand(Query, conDataBase);
MySqlDataReader myReader;
try
{
conDataBase.Open();
myReader = cmdDataBase.ExecuteReader();
while (myReader.Read())
{
string type = myReader.GetString("Type_of_bug");
comboBox1.Items.Add(type);
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
void Fillcombo1()
{
string constring1 = "datasource = localhost; username = root; password = ";
string Query1 = "select * from bug.severity";
MySqlConnection conDataBase1 = new MySqlConnection(constring1);
MySqlCommand cmdDataBase1 = new MySqlCommand(Query1, conDataBase1);
MySqlDataReader myReader;
try
{
conDataBase1.Open();
myReader = cmdDataBase1.ExecuteReader();
while (myReader.Read())
{
string severity = myReader.GetString("severity");
severity_combo.Items.Add(severity);
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
void Fillcombo2()
{
string constring2 = "datasource = localhost; username = root; password = ";
string Query2 = "select * from bug.priority";
MySqlConnection conDataBase2 = new MySqlConnection(constring2);
MySqlCommand cmdDataBase2 = new MySqlCommand(Query2, conDataBase2);
MySqlDataReader myReader;
try
{
conDataBase2.Open();
myReader = cmdDataBase2.ExecuteReader();
while (myReader.Read())
{
string priority = myReader.GetString("priority");
priority_combo.Items.Add(priority);
}
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
}
private void submit_button_Click(object sender, EventArgs e)
{
string constring = "datasource=localhost;username=root;password=";
string Query = "INSERT INTO 'bug.bug' (Bug_ID, title, Type_of_bug, software, software_version, description, step_to_reproduction, severity, priority, symptom) values('" + this.bugid_txt.Text+"', '" + this.title_txt.Text + "','" + this.comboBox1.Text + "','" + this.software_txt.Text + "','" + this.software_version_txt.Text + "','" + this.description_txt.Text + "','" + this.step_to_reproduction_txt.Text + "','" + this.severity_combo.Text + "','" + this.priority_combo.Text + "','" + this.symptom_txt.Text + "');";
MySqlConnection conDataBase = new MySqlConnection(constring);
MySqlCommand cmdDataBase = new MySqlCommand(Query, conDataBase);
MySqlDataReader myReader;
try
{
conDataBase.Open();
myReader = cmdDataBase.ExecuteReader();
MessageBox.Show("Saved");
while(myReader.Read())
{
}
}catch(Exception ex)
{
MessageBox.Show(ex.Message);
}
}
}
请帮帮我:((((
最佳答案
我在您的 INSERT 查询中看到两个语法错误上下文问题
首先，INSERT INTO 'bug.bug'；删除那些单引号，否则它是文字值而不是表名。它应该是 INSERT INTO bug.bug
其次，删除查询语句最后的分号
.... + this.symptom_txt.Text + "');";
^.... this semicolon
关于c# - 在 C# 中出现 SQL 语法错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34576991/