SELECT det.tag_id,det.category_id,det.subcategory_id,det.event_id,dt.tag_name
FROM `do_experience_tags` det
INNER JOIN `do_category` dc ON (det.subcategory_id=dc.`category_id` AND dc.is_master_category=1)
INNER JOIN do_tags dt ON (det.tag_id=dt.tag_id)
tagid catid subcatid event_id tag_name
174 4 25 2 #music
174 4 25 1 #music
如何获取新列中相同标签名的个数
最佳答案
使用count
函数:
SELECT det.tag_id, count(*)
FROM `do_experience_tags` det
INNER JOIN `do_category` dc ON
(det.subcategory_id=dc.`category_id` AND
dc.is_master_category=1)
INNER JOIN do_tags dt ON (det.tag_id=dt.tag_id)
GROUP BY det.tag_id
关于mysql - 获取我的标 checkout 现在 mysql 查询中的计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35218098/